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4 years ago

Can someone help me it’s very easy I just need help!!

Mathematics

1 answer:

beks73 [17]4 years ago

4 0

Answer:

198 m³

Step-by-step explanation:

Find the area of the triangular prism.

3 × 4 × 1/2 × 9

= 54

Find the area of the rectangular prism.

4 × 4 × 9

= 144

Add their areas.

144 + 54 = 198

The area of the composite shape is 198 m³.

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Mark buys a wooden board that is 7 1/2 feet long. The cost of the board is $0.50 per foot, including tax. What is the total cost

artcher [175]

Answer:

Total cost of Mark's board is $3.75.

Step-by-step explanation:

We are given the following in the question:

Length of wooden board =

$=7\dfrac{1}{2}\text{ foot}$

Unit cost of board = $0.50 per foot

Total cost of board =

$=\text{Length of board}\times \text{Unit cost of board}\\\\=7\dfrac{1}{2}\times 0.50\\\\=\dfrac{15}{2}\times \dfrac{1}{2}\\\\=\dfrac{15}{4} = 3.75\$$

Thus, total cost of Mark's board is $3.75.

7 0

3 years ago

Helpppppppppppppppppppppppp

kupik [55]

Answer:

$360\ cm^2$

Step-by-step explanation:

Step 1: Determine the area of the bottom rectangle

$A = l * w$

$A = 10\ cm * 12\ cm$

$A = 120\ cm^2$

Step 2: Determine the area of the back rectangle

$A = l * w$

$A = 10\ cm * 5\ cm$

$A = 50\ cm^2$

Step 3: Determine the area of the top rectangle

$A = l * w$

$A = 10\ cm * 13\ cm$

$A = 130\ cm^2$

Step 4: Determine the area of the triangle

$A = \frac{h*b}{2}$

$A = \frac{5\ cm * 12\ cm}{2}$

$A = \frac{60\ cm^2}{2}$

$A = 30\ cm^2$

Step 5: Determine the surface area

$120\ cm^2 + 50\ cm^2 + 130\ cm^2 + 2(30\ cm^2)$

$360\ cm^2$

Answer: $360\ cm^2$

4 0

3 years ago

it took 8 quarts of paint to paint two sides of a garage. If the third side is the same size as each of the first two sides, how

zysi [14]

Its i don't know i eally did nt mean to sau that

5 0

4 years ago

Triangle KJL is inscribed in semicircle O shown below such that JK=6 and JL=11. Which of the following is closest to the radius

lakkis [162]

Uhh, answer choices?

In any case, since $\triangle KJL$ is inscribed in a semicircle, it is a right triangle (due to the inscribed angle theorem). Thus, by the Pythagorean theorem, $KL=\sqrt{6^2+11^2}=\sqrt{157}.$ Now, the circumradius of a right triangle (the radius of the circle passing through all three of its vertices) is simply half its hypotenuse, so $OJ=OK=OL=\frac{\sqrt{157}}{2}\approx \boxed{6.265}.$