A model airplane is flying north with a velocity of of 15m/s. A strong wind blowing east at 12m/s
1 answer:
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Answer:
The electric field is directed toward the electron and has a magnitude of .
Explanation:
An electric field is define as the surrounding of charges which exert a force on each other and this force can be attractive or repulsive depends on the charge.
In the given case electron is given and the magnitude of charge on electron is
Electric field can be represented as,
Here, r is the distance between the point ande charge, k is the electric field constant and Q is the charge.
In the given question an electron is given so electric field will be,
As we know that electric field start from the positive charge and vanish in the negative charge.
So, here the electric field will be and it is directed toward the electron because of negative charge on the electron.
Answer:
The momentum is 1.94 kg m/s.
Explanation:
To solve this problem we equate the potential energy of the spring with the kinetic energy of the ball.
The potential energy of the compressed spring is given by
,
where is the length of compression and
is the spring constant.
And the kinetic energy of the ball is
When the spring is released all of the potential energy of the spring goes into the kinetic energy of the ball; therefore,
solving for we get:
And since momentum of the ball is ,
Putting in numbers we get: