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NISA [10]
3 years ago
15

3. A 0.5L container of Nitrogen (N) gas at 18 degrees Celsius is heated under constant pressure to the boiling point of water. W

hat is its new volume?
Chemistry
1 answer:
ExtremeBDS [4]3 years ago
8 0

The volume increased to 0.64 L on increasing the temperature to boiling point of water.

<u>Explanation:</u>

One of the important laws used for understanding the kinetics of gas particles is Charle's law. It states that the volume occupied by gas molecules will be directly proportional to the Kelvin temperature of the molecules at constant pressure.

Volume ∝ Kelvin Temperature at constant Pressure

So, in this case, the initial volume of the container in which Nitrogen gas is kept is given as 0.5 L and the initial temperature of the Nitrogen gas is said to be 18°C.

Now the container is heated to boiling point of water which is 100°C, then the volume occupied by the gas should increase as per Charle's law.

\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

Since here V₁ = 0.5 L

T₁ = 18°C =  18 + 273.15 = 291.15 K

T₂ = 100°C = 100 + 273.15 = 373.15 K

\frac{0.5}{291.15} = \frac{V_{2} }{373.15} \\\\V_{2} = \frac{0.5 \times 373.15}{291.15} = 0.64\ L

Thus, the volume increased to 0.64 L on increasing the temperature to boiling point of water.

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sleet_krkn [62]

Answer:- 29.6 moles of carbon.

Solution:- We have been given with 3.7 moles of C_8H_11NO_2 and asked to calculate the moles of C.

Looking at the formula of the compound, there are 8 carbons in it means 1 mol of he compound has 8 moles of C. So, if we multiply the given moles of the compound by 8 then we get the moles of C.

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= 29.6 mol C

Hence. there are 29.6 moles of C in 3.7 moles of  C_8H_11NO_2  .

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What is a molarity a measurement
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3 years ago
A 50.6 grams sample of magnesium hydroxide (Mg(OH)2) is reacted with 45.0 grams of hydrochloric acid (HCl). What is the theoreti
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Consider the reaction pathway graph below.
Alex17521 [72]
Hello!

The reaction that the graph represents is A. Exothermic because Hrxn=-167 kJ

To calculate Hrxn we apply the following equation:

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