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MatroZZZ [7]
4 years ago
12

What is the parallel axis theorem and how is it used? Please explain the equation.

Physics
1 answer:
Tema [17]4 years ago
7 0

Explanation:

If an object has a moment of inertia I₀ about an axis, then the moment of inertia about a different, parallel axis is I = I₀ + md², where d is the distance between the axes.

For example, consider a horizontal thin rod rotating about a vertical axis passing through its center.  It has mass m and length L.  Its moment of inertia is known to be I = 1/12 mL².

Now consider the same rod, but this time we move the axis of rotation L/2 to the end of the rod.  We can use parallel axis theorem to find the new moment of inertia:

I = I₀ + md²

I = 1/12 mL² + m (L/2)²

I = 1/12 mL² + 1/4 mL²

I = 1/3 mL²

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A raindrop falls to the ground from a rain cloud at an altitude of 3000 meters.
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Assuming the raindrop was stationary relative to the vertical distance to the ground at the start:

D=0.5at where d is distance, a is acceleration and t is time

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2 years ago
A projectile is fired at an upward angle of 35.6° from the top of a 208-m-high cliff with a speed of 170-m/s. What will be its s
sdas [7]

Answer:

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

Explanation:

Initial horizontal velocity = 170 cos 35.6 = 138.23 m/s

Final horizontal velocity = 138.23 m/s

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Initial vertical velocity, u = 170 sin 35.6 = 98.96 m/s

Acceleration, a = -9.81 m/s²

Displacement, s = -208 m

We have v² = u² + 2as

Substituting

             v² = 98.96² + 2 x -9.81 x -208

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            v=\sqrt{138.23^2+117.79^2}=181.61m/s

            \theta =tan^{-1}\left ( \frac{117.79}{138.23}\right )=40.44^0

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

5 0
4 years ago
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