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3 years ago

Please help. Idk what to do. Please

Chemistry

1 answer:

Inga [223]3 years ago

5 0

Answer:

7. orbit

8. A comet

9.gas giant

10.moons

11.gravity

12.meteoroids

13.craters

14.super sized

Explanation: idk if 14 is right but yea your welcome

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Each of the following reactions is allowed to reach equilibrium in a sealed container. For which of the reactions could you shif

natta225 [31]

Answer:

None of the reaction will be favored to the right by a decrease in pressure.

Explanation:

CH₄(g) + 2O₂(g) ⇄ CO₂(g) + 2H₂O(l)

CaCO₃(s) ⇄ CaO(s) + CO₂(g)

Br₂(g) + 3Cl₂(g) ⇄ 2BrCl₃(g)

2H₂S(g) + 3O₂(g) ⇄ 2SO₂(g) + 2H₂O(g)

From Le Chatellier's principle, we must understand that pressure changes only affects reactions in gaseous phases. The second reaction will not be affected by pressure.

We are now left with three equations.

Also, increase in pressure favors sides with lower volume. We can know the volume from the coefficients in the equation. Now let us check the volumes:

CH₄(g) + 2O₂(g) ⇄ CO₂(g) + 2H₂O(l)

3 moles of gases 3 moles of gases

Br₂(g) + 3Cl₂(g) ⇄ 2BrCl₃(g)

4 moles of gases 2 moles of gases

2H₂S(g) + 3O₂(g) ⇄ 2SO₂(g) + 2H₂O(g)

5 moles of gases 4 moles of gases

None of the reaction will be favored to the right by a decrease in pressure.

The first reaction will not be affected by any change in pressure because the total number of moles on the two sides are equal.

The last two reactions will be favored to the right by increasing pressure and a decrease in pressure will favor the backward left reaction.

7 0

3 years ago

Read 2 more answers

Suppose of barium acetate is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of barium cati

ollegr [7]

Explanation:

Let us assume that the given data is as follows.

mass of barium acetate = 2.19 g

volume = 150 ml = 0.150 L (as 1 L = 1000 ml)

concentration of the aqueous solution = 0.10 M

Therefore, the reaction equation will be as follows.

$Ba(C_{2}H_{3}O_{2})_{2} \rightarrow Ba^{2+} + 2C_{2}H_{3}O^{-}_{2}$

Hence, moles of $C_{2}H_{3}O^{-}_{2}$ = $2 \times Ba(C_{2}H_{3}O_{2})_{2}$ .......... (1)

As, No. of moles = $\frac{mass}{\text{molar mass}}$

Hence, moles of $Ba(C_{2}H_{3}O_{2})_{2}$ will be calculated as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{2.19 g}{255.415 g/mol}$ (molar mass of $Ba(C_{2}H_{3}O_{2})_{2}$ is 255.415 g/mol)

= $8.57 \times 10^{-3}$

Moles of $C_{2}H_{3}O^{-}_{2}$ = $2 \times 8.57 \times 10^{-3}$

= 0.01715 mol

Hence, final molarity will be as follows.

Molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{0.01715 mol}{0.150 L}$

= 0.114 M

Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.

5 0

3 years ago

The Lewis dot model of a metal atom has two dots. Which of the following is true about the atom?

a_sh-v [17]

Answer:

It is present in the second group of the periodic table

Explanation:

7 0

3 years ago

Read 2 more answers

The coefficients in a chemical equation represent the

expeople1 [14]

Answer:

The coefficients in a chemical equation represent the relative number of moles of each reactant and product that interven in the chemical reaction.

Explanation:

The coefficients are the numbers that you put in front of each chemical formula that represents the reactants and products in the chemical equation. They indicate the mole ratio in which the elements or compounds react to form the products, as per the chemical equation.

See an example:

Word equation: hydrogen and oxygen produce water

Chemical (skeleton) equation: H₂ (g) + O₂(g) → H₂O (g)

This equation is not balanced: the number of atoms of oxygenin the reactant side is 2 while the number of atoms of oxygen isn the product side is 1. In order to balance the equation you need to add some coefficients.

When no coefficients are shown it is understood that the coefficient is 1.

Balanced chemical equation: 2H₂ (g) + O₂(g) → 2H₂O (g)

The coefficients 2 in front of H₂ and 1 (understood) in front of O₂, in the reactant side, and 2 in front of H₂O, in the product side, balance the equation.

Those coefficients mean that the 2 molecules (or mole of molecules) of H₂ react with 1 molecule (or mole of molecules) of O₂ to form 2 molecules (or moles) of H₂O (product side).

That is the mole ratio: 2 H₂ : 1 O₂ : 2 H₂O.

Notice that, in spite of the aboslute numbers may change, the mole ratio is unique for any chemical reaction. For example 4 : 2 : 4 is the same ratio that 2 : 1 : 2, or 8 : 4 : 8, but the most common practice is to use the most simple form of the ratio, i.e. 2: 1: 2.

7 0

2 years ago

Halogens on directly opposite carbons in a benzene ring are in the:

Naddik [55]

I think it is Para-position.

4 0

3 years ago