A sample of water with a mass of 1 gram freezes at 32°F. At what temperature will a 100-gram sample of water freeze?

What is the symbol SI unit of time?

Vsevolod [243]

Answer:

second is the SI unit of time

7 0

3 years ago

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In a gravitational-free environment, an object of unknown mass is connected to a spring with k = 40 N/m. The spring is compresse

iVinArrow [24]

Newton's Third Law of Motion states that springs exert a restoring force when they are pulled. The relationship between the spring force, spring constant, and spring displacement is governed by Hooke's Law.

Mass of the object= k*x/a= 26kg

what is Hooke's law?

The force (F) required to extend or compress a spring by a certain distance (x) scales linearly with respect to that distance, according to the empirical law known as Hooke's law.

according to Hooke's law

f=-k x (-ve because spring is compressing)

from force equation f=ma m-=mass, a= acceleration , k=spring constant, x= displacemt due to compression

so, ma=-k x, (mass can not be -ve so remove -ve sign)

m=k x/a= 40*2/3=26.67 kg

To learn more about : Hooke's law

Ref : brainly.com/question/7324904

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5 0

2 years ago

A horizontal force, F1 = 65 N, and a force, F2 = 12.4 N acting at an angle of θ to the horizontal, are applied to a block of mas

Nezavi [6.7K]

Answer:

(a) FN = 24.18 N

(b) a = 22.87 m/s²

Explanation:

Newton's second law of the block:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Forces acting on the box

We define the x-axis in the direction parallel to the movement of the block on the surface and the y-axis in the direction perpendicular to it.

F₁ : Horizontal force

F₂ : acting at an angle of θ to the horizontal,

W: Weight of the block : In vertical direction

FN : Normal force : perpendicular to the direction the surface

fk : Friction force: parallel to the direction to the surface

Known data

m =3.1 kg : mass of the block

F₁ = 65 N, horizontal force

F₂ = 12.4 N acting at an angle of θ to the horizontal

θ = 30° angle θ of F₂ with respect to the horizontal

μk = 0.2 : coefficient of kinetic friction between the block and the surface

g = 9.8 m/s² : acceleration due to gravity

Calculated of the weight of the block

W= m*g = (3.1 kg)*(9.8 m/s²) = 30.38 N

x-y F₂ components

F₂x = F₂cos θ= (12.4)*cos(30)° = 10.74 N

F₂y = F₂sin θ= (12.4)*sin(30)° = 6.2 N

a)Calculated of the Normal force (FN)

We apply the formula (1)

∑Fy = m*ay ay = 0

FN+6.2-30.38 = 0

FN = -6.2+30.38

FN = 24.18 N

Calculated of the Friction force:

fk=μk*N= 0.2* 24.18 N = 4.836 N

b) We apply the formula (1) to calculated acceleration of the block:

∑Fx = m*ax , ax= a : acceleration of the block

F₁ + F₂x -fk = ( m)*a

65 N + 10.74 -4.836 = ( 3.1)*a

70.904 = ( 3.1)*a

a = (70.904 ) / ( 3.1)

a = 22.87 m/s²

4 0

3 years ago

What are the two forces that keep a pendulum swinging?

Nezavi [6.7K]

The force of gravity is the only force that keeps a pendulum in motion. both the force increases the speed of the pendulum on the downswing and decreases it's speed on its upswing.

3 0

3 years ago

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Given a block of glass that is semi-circular, a laser pointer, protractor/ruler, and index card, design your own experiment to o

Charra [1.4K]

Answer:

we go up the ramp there is a point where the beam is reflected inside the block, we carefully step back to the point where the beam is horizontal, we measure this angle which is our critical angle.

Explanation:

To design the experiment of measuring the critical angle, we describe the phenomenon, when the light passes from a medium with a higher refractive index to one with a lower index, it separates from the normal one and the Critical Angle is defined as the Angle for which the refraction occurs at 90º

n₂ sin θ₂ = n₁ sin 90

n₁ / n₂ = sin θ₂

As we can see, we have to measure the angle with which the laser touches the exit surface of the glass block.

Design of the experiment:

We place the glass block on the ramp and at the top we hit the conveyor for half the angle, we climb the block on the ramp and see that the angle of incidence of lightning on the exit face changes, part of the beam comes out of the glass , we see it by dispersion in the particles of dirty in the air; Maybe the conveyor or the laser should be moved slightly so that the beam touches the point of origin on the conveyor.

When we go up the ramp there is a point where the beam is reflected inside the block, we carefully step back to the point where the beam is horizontal, we measure this angle which is our critical angle.

5 0

3 years ago

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