The only thing that definitely happens in every such case is:
The container becomes heavier.
Answer:
Intensity of the light (first polarizer) (I₁) = 425 W/m²
Intensity of the light (second polarizer) (I₂) = 75.905 W/m²
Explanation:
Given:
Unpolarized light of intensity (I₀) = 950 W/m²
θ = 65°
Find:
a. Intensity of the light (first polarizer)
b. Intensity of the light (second polarizer)
Computation:
a. Intensity of the light (first polarizer)
Intensity of the light (first polarizer) (I₁) = I₀ / 2
Intensity of the light (first polarizer) (I₁) = 950 / 2
Intensity of the light (first polarizer) (I₁) = 425 W/m²
b. Intensity of the light (second polarizer)
Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ
Intensity of the light (second polarizer) (I₂) = (425)(0.1786)
Intensity of the light (second polarizer) (I₂) = 75.905 W/m²
Answer:
![\Phi_{E} = E\pi r^2 \omega t](https://tex.z-dn.net/?f=%5CPhi_%7BE%7D%20%3D%20E%5Cpi%20r%5E2%20%5Comega%20t)
Explanation:
The electric flux is defined as the multiple of electric field and the area that the electric field passes through, such that
![\Phi_{E} = \vec{E}\vec{A}](https://tex.z-dn.net/?f=%5CPhi_%7BE%7D%20%3D%20%5Cvec%7BE%7D%5Cvec%7BA%7D)
When calculating the electric flux, the angle between the directions of electric field and the area becomes important, especially if the angle is changing with time.
The above formula can be rewritten as follows
![\Phi_{E} = EA\cos(\theta)](https://tex.z-dn.net/?f=%5CPhi_%7BE%7D%20%3D%20EA%5Ccos%28%5Ctheta%29)
where θ is the angle between the electric field and the area of the loop. Note that, the direction of the area of the loop is perpendicular to the plane of the loop.
If the loop is rotating with constant angular velocity ω, then the angle can be written as follows
![\theta = \omega t](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Comega%20t)
At t = 0, cos(0) = 1 and the electric flux through the loop is at its maximum value.
Therefore the electric flux can be written as a function of time
![\Phi_{E} = E\pi r^2 \omega t](https://tex.z-dn.net/?f=%5CPhi_%7BE%7D%20%3D%20E%5Cpi%20r%5E2%20%5Comega%20t)
To solve this problem, use the ratio given by the total number of electrons or protons that exist as a function of the total charge, and inversely proportional to the value of the fundamental charge. The number of fundamental unit
that constitutes a charge of 40.0C can be calculated as
![N = \frac{|Q|}{|q_e|}](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B%7CQ%7C%7D%7B%7Cq_e%7C%7D)
Here,
= Value of charge and it is the fundamental charge
Q = Total Charge
N = Total number of electron or protons
The number of fundamental units is calculated as follows
![N = \frac{10.0C}{1.6*10^{-19}C}](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B10.0C%7D%7B1.6%2A10%5E%7B-19%7DC%7D)
![N = 6.25*10^{19}](https://tex.z-dn.net/?f=N%20%3D%206.25%2A10%5E%7B19%7D)
Therefore the number of fundamental charge units moved by lightning bolt is ![6.25*10^{19}](https://tex.z-dn.net/?f=6.25%2A10%5E%7B19%7D)
Air is the answer i do believe