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Yakvenalex [24]
3 years ago
14

A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne. The partial pressu

re of Ne is ________ atm.
Chemistry
1 answer:
dangina [55]3 years ago
4 0

Answer:

Partial pressure of Ne is 0.61 atm.

Explanation:

Mole fraction of a gas (x) in mixture = (no. of moles of the gas in mixture)/(total no. of moles of gases in mixture)

Here, total no. of moles of gases = (0.32 + 0.56) moles = 0.88 moles

So, mole fraction of Ne in mixture, x_{Ne}=\frac{0.56}{0.88}=0.64

Let's assume both He and Ne along with their mixture behaves ideally,

Hence, in accordance with Dalton's law of partial pressure-

                     P_{Ne}=x_{Ne}\times P_{total}

Where, P_{Ne} and P_{total} are partial pressure of Ne and total pressure respectively.

So,  P_{Ne}=(0.64)\times (0.95atm)=0.61atm

So, partial pressure of Ne is 0.61 atm.

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