Question

A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne. The partial pressure of Ne is ________ atm.

Answer 1

Answer:

Partial pressure of Ne is 0.61 atm.

Explanation:

Mole fraction of a gas $(x)$ in mixture = (no. of moles of the gas in mixture)/(total no. of moles of gases in mixture)

Here, total no. of moles of gases = (0.32 + 0.56) moles = 0.88 moles

So, mole fraction of Ne in mixture, $x_{Ne}=\frac{0.56}{0.88}=0.64$

Let's assume both He and Ne along with their mixture behaves ideally,

Hence, in accordance with Dalton's law of partial pressure-

                     $P_{Ne}=x_{Ne}\times P_{total}$

Where, $P_{Ne}$ and $P_{total}$ are partial pressure of Ne and total pressure respectively.

So,  $P_{Ne}=(0.64)\times (0.95atm)=0.61atm$

So, partial pressure of Ne is 0.61 atm.