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3241004551 [841]
3 years ago
12

A racehorse coming out of the gate accelerates from rest to a velocity of 12.0

Physics
1 answer:
Natali [406]3 years ago
6 0

Answer:

5.22 m/s²

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 12 m/s

Time (t) = 2.3 s

Acceleration (a) =.?

Acceleration is defined as the change of velocity with time. Mathematically, it is expressed as:

Acceleration (a) = final velocity (v) – initial velocity (u) / time (t)

a = (v – u) /t

With the above formula, we can obtain the acceleration of the racehorse as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 12 m/s

Time (t) = 2.3 s

Acceleration (a) =.?

a = (v – u) /t

a = (12 – 0) / 2.3

a = 12 /2.3

a = 5.22 m/s²

Therefore, the average acceleration of the racehorse is 5.22 m/s²

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a motorcycle traveling on the highway at a velocity of 120 kilometre-per-hour passes a car traveling at a velocity of 90 kilomet
musickatia [10]

Answer:

The relative velocity of the motorcycle to a passenger in the car is 30 km/h

Explanation:

The question relates to the principle of relative velocity and reference frames

The given parameters are;

The velocity of the motorcycle, v₁ = 120 km/h

The velocity of the car, v₂ = 90 km/h

The relative velocity of an object X with regards to another object Y is the velocity the object X will seem to be moving with to an observer in the rest frame of object Y written as \underset{v}{\rightarrow}_{X|Y} = \underset{v}{\rightarrow}_{X} - \underset{v}{\rightarrow}_{Y}

Therefore, the relative velocity of the motorcycle to the car is v_{1|2} = v₁ -  v₂, which give;

v_{1|2}  = 120 km/h - 90 km/h = 30 km/h

The relative velocity of the motorcycle to a passenger in the car = 30 km/h.

5 0
3 years ago
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57×10−21 n
hichkok12 [17]

Answer:

891 excess electrons must be present on each sphere

Explanation:

One Charge = q1 = q

Force = F = 4.57*10^-21 N  

Other charge = q2 =q

Distance = r = 20 cm = 0.2 m  

permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)  

Using Coulomb's law,

F=[1/4pieo]q1q2/r^2

F = [1/4pieo]q^2 / r^2

q^2 =F [4pieo]r^2

q =  r*sq rt F[4pieo]

 q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]

q = 1.42614*10^ -16 C

number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19

n =891

 891 excess electrons must be present on each sphere  

5 0
3 years ago
A loop of wire is placed in a uniform magnetic field. Let ø be the angle between the direction of b and the normal. At which val
zaharov [31]

Answer:

B. 0 degrees

Explanation:

The magnetic flux through a certain area enclosed by a loop of wire immersed in a region with magnetic field is given by:

\Phi = B A cos \theta

where

B is the strength of the magnetic field

A is the area enclosed by the coil

\theta is the angle between the direction of the magnetic field and the direction of the normal to the coil

From the equation above, we see that the magnetic flux is maximum when

cos \theta=1

So when the field is parallel to the normal to the coil (so, when it is perpendicular to the coil), therefore when:

\theta=0^{\circ}

So, the correct option is

B. 0 degrees

5 0
4 years ago
Why is a protective apron or lab coat important to use when working with acids?
Oksanka [162]

Answer: Option (C) is the correct answer.

Explanation:

Whether an acid is weak or strong it will cause harm if it comes in direct contact with the skin, eyes or mouth etc.

Thus, in order to prevent oneself, it is advised to wear a lab coat while working in laboratory as acids break down fabrics and can cause burns if the acids are strong.

Hence, a lab coat acts as a protective layer on the clothes so that even if acid falls on it then it might not reach the skin immediately and on time prevention can be taken.

6 0
3 years ago
Read 2 more answers
What type of nuclear decay releases energy but not a particle?
statuscvo [17]
I believe gamma decay but i may be wrong
7 0
3 years ago
Read 2 more answers
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