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3 years ago

Read about Pendulums. Then complete the sentences based on the diagram of the pendulum. Be sure to keep this

Physics

2 answers:

marin [14]3 years ago

5 0

Answer:

The pendulum has the most potential energy .

The pendulum has the least kinetic energy .

The pendulum has the most kinetic energy .

The pendulum has the least potential energy .

1) at the top of the swing

2) at the top of the swing

3) at the bottom of the swing

4) at the bottom of the swing

Explanation:

just did it, it's right. (EDGE 2020)

MrRissso [65]3 years ago

3 0

Answer:

Potential Energy is given as:

P.E = mgh

which means P.E is directly proportional to height 'h'.

Kinetic Energy is given as:

K.E = (1/2)mv²

which means K.E is directly proportional to velocity 'v²'.

Total Energy of Pendulum = K.E + P.E

1. The pendulum has the most potential energy at extreme position because the height is maximum at the extreme position.

2. The pendulum has the least kinetic energy at extreme position because the velocity is zero at extreme position.

3. The pendulum has most kinetic energy at the mean position because the velocity is maximum at this point.

4. The pendulum has the least potential energy at the mean position because the height is minimum.

A rule to remember: The point where K.E is maximum, P.E is zero at this point and vice versa.

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A parallel-plate vacuum capacitor has 8.60 J of energy stored in it. The separation between the plates is 3.80 mm . If the separ

creativ13 [48]

Answer:

Part a)

$E = \frac{8.60}{2.62} = 3.28 J$

Part b)

$E = 2.62(8.60) = 22.5 J$

Explanation:

As we know that the energy of capacitor when it is not connected to potential source is given as

$U = \frac{Q^2}{2C}$

As we know that initial energy is given as

$8.60 = \frac{Q^2}{2C}$

now we know that capacitance of parallel plate capacitor is given as

$C = \frac{\epsilon_0A}{d}$

now the new capacitance when distance is changed from 3.80 mm to 1.45 mm

$C' = \frac{Cd}{d'}$

$C' = \frac{C(3.80)}{1.45}$

$C' = 2.62 C$

Now the new energy of the capacitor is given as

$E = \frac{Q^2}{2(2.62C)}$

$E = \frac{8.60}{2.62} = 3.28 J$

Part b)

Now if the voltage difference between the plates of capacitor is given constant

now the energy energy of capacitor is

$U = \frac{1}{2}CV^2$

$8.60 = \frac{1}{2}CV^2$

now when capacitance is changed to new value then new energy is given as

$E = \frac{1}{2}C'V^2$

$E = \frac{1}{2}(2.62C)V^2$

$E = 2.62(8.60) = 22.5 J$

6 0

3 years ago

What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged partic

VladimirAG [237]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$v_w = 2.256 *10^{8} \ m/s$

$v_e = 2.21 *10^{8} \ m/s$

The correct option is B

Explanation:

From the question we are told that

The refractive index of water is $n_w = 1.33$

The refractive index of ethanol is $n_e = 1.36$

Generally the threshold velocity for creating Cherenkov light from a charged particle as it travels through water is mathematically evaluated as

$v_w = \frac{c}{n_w }$

Where c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

$v_w = \frac{3.0 *10^{8}}{1.33 }$

$v_w = 2.256 *10^{8} \ m/s$

Generally the threshold velocity for creating Cherenkov light from a charged particle as it travels through water is mathematically evaluated as

$v_e = \frac{ c}{n_e }$

=> $v_e = \frac{3.0 *10^{8}}{1.36 }$

=> $v_e = 2.21 *10^{8} \ m/s$

4 0

3 years ago

A student rides a bicycle for 15 miles in 3 hours. What is the student's speed? What else would you need to know for the velocit

kaheart [24]

Answer:

5 miles per hour

Explanation:

if you divide 15 by 3 you get 5, therefore the student is going 5 miles per hour.

3 0

2 years ago

A speed-time graph is shown below:

Juliette [100K]

Answer:

It traveled 4 centimeters.

Explanation:

In a speed versus time graph, the distance travelled is given by the area under the graph.

In this graph we have the following:

- The speed of the object is v = 1 cm/s between time t = 0 s and t = 4 s

- The speed of the object is v = 0 cm/s between time t = 4 s and t = 8 s

Since the speed in the second part is zero, the distance travelled in the second part is zero. So, the only distance travelled by the object is the distance travelled during the first part, which is equal to the area of the first rectangle:

$d=v\Delta t=(1)(4-0)=4 cm$

4 0

3 years ago

When developing an experimental design, which action would improve the

il63 [147K]

When developing an experimental design, the action that would improve the quality of the results is to ensure that it answers a question about cause and effect.

<h3>What is experimental design?</h3>

Experimental design is a concept used to organize, conduct, and interpret results of experiments in an efficient way, making sure that as much useful information as possible is obtained by performing a small number of trials.

Thus, when developing an experimental design, the action that would improve the quality of the results is to ensure that it answers a question about cause and effect.

Learn more about experimental design here: brainly.com/question/17274244

#SPJ1

8 0

1 year ago