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Sergeu [11.5K]
3 years ago
6

Which reaction below represents a balanced, double replacement chemical reaction? A) C2H5OH + 3O2 → 2CO2 + 3H2O B) Rb2O + Cu(C2H

3O2)2 → 2RbC2H3O2 + CuO C) 2Al + 3H2SO4 → 3H2 + Al2(SO4)3 Eliminate D) 2H2O → 2H2 + O2
Chemistry
2 answers:
guajiro [1.7K]3 years ago
8 0
Option B. <span>Rb2O + Cu(C2H3O2)2 → 2RbC2H3O2 + CuO is the correct answer. HOPE IT HELPS</span>
julia-pushkina [17]3 years ago
7 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Double displacement reaction is defined as the reaction in which exchange of ions takes place.

AB+CD\rightarrow CB+AD

For the given options:

  • <u>Option A:</u>

The chemical equation follows:

C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O

This is a type of combustion reaction because an organic compound reacts with oxygen gas to produce carbon dioxide gas and water molecule

  • <u>Option B:</u>

The chemical equation follows:

Rb_2O+Cu(C_2H_3O_2)_2\rightarrow 2RbC_2H_3O_2+CuO

This is a type of double displacement reaction.

  • <u>Option C:</u>

The chemical equation follows:

2Al+3H_2SO_4\rightarrow 3H_2+Al_2(SO_4)_3

This is a type of single displacement reaction because a more reactive metal (aluminium) is replacing a less reactive metal (hydrogen).

  • <u>Option D:</u>

The chemical equation follows:

2H_2O\rightarrow 2H_2+O_2

This is a type of decomposition reaction because a single large compound is getting broken down to smaller substances.

Hence, the correct answer is Option B.

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Why is pseudo science not considered real science
swat32

Pseudo-science is not considered real science because it is not testable.

Answer:  Option A

<u>Explanation:</u>

Pseudoscience primarily includes beliefs, theories or practices that are somehow incompatible with the scientific facts. The pseudoscience can’t be tested on the basis of science.

Let’s take an example of astrology. Some people believe that stars and other celestial bodies draw a significant impact on their life i.e. Good or bad thing it's just because their stars are working either in a positive or negative manner.

But, this belief doesn’t have any well-proved or authentic background over which the whole concept can rely on. Hence, pseudoscience is not taken as a real science as a lack of strong proves.

8 0
3 years ago
The base-dissociation constant, kb, for pyridine, c5h5n, is 1.4x10-9 the acid-dissociation constant, ka, for the pyridinium ion,
sp2606 [1]
We are given the base dissociation constant, Kb, for Pyridine (C5H5N) which is 1.4x10^-9. The acid dissociation constant, Ka for the Pyridium ion or the conjugate acid of Pyridine is to be determined. We know from our chemistry classes that:

Kw = Kb * Ka

where Kw is always equal to 1x10^-14

so, to solve for Ka of Pyridium ion, substitute Kb to the equation together with Kw and solve for Ka:

1x10^-14 = 1.4x10^-9 * Ka
solve for Ka

Ka = 7.14x10^-6 

Therefore, the acid dissociation constant of Pyridinium ion is 7.14x10^-6.
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5 0
3 years ago
A sample of gas occupies 300 mL at 100K. What is its volume when the
iris [78.8K]

If the temperature of the sample of gas increases to the given value, the volume also increases to 600mL.

<h3>What is Charles's law?</h3>

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

  • Initial temperature of gas T₁ = 100K
  • Initial volume of gas V₁ = 300mL
  • Final temperature T₂ = 200K
  • Final volume V₂ = ?

V₁/T₁ = V₂/T₂

V₂ = V₁T₂ / T₁

V₂ = ( 300mL × 200K ) / 100K

V₂ = 60000mLK / 100K

V₂ = 600mL

Therefore, if the temperature of the sample of gas increases to the given value, the volume also increases to 600mL.

Learn more about Charles's law here: brainly.com/question/12835309

#SPJ1

3 0
2 years ago
Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water
barxatty [35]

Molarity after dilution : 0.0058 M

<h3>Further explanation </h3>

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M

5 0
3 years ago
I'd: 9872093250, password: qqqqq, join the meeting​
Sonja [21]
You keep on saying join fast wdym?!
4 0
2 years ago
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