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svp [43]
3 years ago
14

A bicycle rider is applying a force of 20 N while heading south against a wind blowing from the south with a force of 5 N

Chemistry
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer:

the bike will go down 5 N

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The motion of the wind can turn wind turbines
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3 years ago
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in 1965, the mean price of a new car was $2,650 and the standard deviation was $1,000. In 2011, the mean was $30,500 and the sta
miss Akunina [59]

Answer:

Car were more expensive in 2011

Explanation:

Data provided in the question:

Mean price of the car in 1965 = $2,650

Standard deviation, s = $1,000

Mean price of the car in 2011 = $30,500

Standard deviation in 2011, s = $9,000

Cost in 1965 = $2,300

Cost in 2011 = $28,000

Now,

z score = [ X - mean ] ÷ s

Therefore,

In 1965

z score = [ $2,300 - $2,650] ÷ 1,000

= -0.35

In 2011

z score = [ $28,000 - $30,500 ] ÷ 9,000

= -0.278

Since,

The standard score in 2011 is higher than in 1965

Hence,

Car were more expensive in 2011

8 0
3 years ago
Which of these chemical formulas represents both an element and a molecule?
inna [77]
O2.

Because it is only made up of one type of element it is an element. Howevern there is more than one oxygen atom because oxygen cannot exist as a single atom, therefore making it a molecule as well.
8 0
2 years ago
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Which would be the best material to use for making tea kettles?
Wewaii [24]
It’s a subjective answer but glass is believed to be the most safe material to use for tea kettles
6 0
3 years ago
Th e molar absorption coeffi cients of tryptophan and tyrosine at 240 nm are 2.00 × 103 dm3 mol−1 cm−1 and 1.12 × 104 dm3 mol−1
nataly862011 [7]

Answer:

5.43x10⁻⁵ dm³mol⁻¹= Concentration of tyrosine

2.58x10⁻⁵ dm³mol⁻¹= Concentration of tryptophan

Explanation:

Lambert-Beer law is:

A = E×C×l

Where A is measured absorbance, E is absorption coefficient, C is concentration of solution and l is optical path length.

For the result at 240nm, it is possible to write:

0.660 = 2.00x10³ dm³mol⁻¹cm⁻¹× Ctry × 1cm + 1.12x10⁴ dm³mol⁻¹cm⁻¹× Ctyr × 1cm <em>(1)</em>

At 280 nm:

0.221 = 5.40x10³ dm³mol⁻¹cm⁻¹× Ctry × 1cm + 1.50x10³ dm³mol⁻¹cm⁻¹× Ctyr × 1cm <em>(2)</em>

<em></em>

Thus:

-2.7× (0.660 = 2.00x10³ × Ctry  + 1.12x10⁴ × Ctyr) =

-1.782 = -5.40x10³Ctry - 3.024x10⁴Ctyr

0.221 = 5.40x10³ × Ctry + 1.50x10³  × Ctyr

-------------------------------------------------------------------

-1.561 = -28740×Ctyr

<em>5.43x10⁻⁵ dm³mol⁻¹= Ctyr</em>

Replacing this value in (1) or (2) it is possible to find Ctry, that is:

<em>2.58x10⁻⁵ dm³mol⁻¹= Ctry</em>

4 0
3 years ago
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