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CaHeK987 [17]
3 years ago
5

You make the following measurements of an object 42kg and 22m3 what would the objects density be?

Chemistry
1 answer:
marissa [1.9K]3 years ago
6 0
Density = 1.91 kg/m^3

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BRAINLIESTTT ASAP!! PLEASE HELP ME :)
a_sh-v [17]

Answer: true

Explanation:

3 0
3 years ago
6. What is the mass of the object if the net force acting on it was 356 N and the acceleration rate
Marina86 [1]

The mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.

<h3>How to calculate mass?</h3>

The mass of an object can be calculated using the following formula:

F = ma

Where;

  • F = force (N)
  • m = mass (kg)
  • a = acceleration (m/s²)

m = F/a

m = 356/4

m = 89kg

Therefore, the mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.

Learn more about mass at: brainly.com/question/19694949

8 0
2 years ago
The Law of Conservation of Matter describes how mass is not lost during a chemical reaction.
weeeeeb [17]

False, it states that matter can be nether created nor destroyed

7 0
2 years ago
Read 2 more answers
What is the volume of 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)?
uysha [10]
Given:
<span> 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)
Required:
volume of CL2
Solution:
Use the ideal gas law
PV = nRT
V = nRT/P
V = (2.1 moles Cl2) (0.08203 L - atm / mol - K) (273K) / (1 atm)
V = 47 L</span>
5 0
3 years ago
What is the ph of a solution of 0.550 m k2hpo4, potassium hydrogen phosphate?
Solnce55 [7]
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+  + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:

PH= -㏒[H+]
     = -㏒(4.81x10^-7) = 6.32

3 0
3 years ago
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