1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
adell [148]
3 years ago
11

Which has the lowest freezing point?

Chemistry
1 answer:
Volgvan3 years ago
5 0

Answer:

Mercury has the lowest freezing point for metals, but helium takes the winner for all substances.

Explanation:

You might be interested in
A gaseous mixture of o2 and n2 contains 35.8 % nitrogen by mass. what is the partial pressure of oxygen in the mixture if the to
lubasha [3.4K]
The partial pressure is the amount of linguistic compound there is which makes the lagitude of the element 64.663
5 0
3 years ago
Calculate the equilibrium number of vacancies per cubic meter for copper at 1000K. The energy for vacancy formation is 0.9eV/ato
nexus9112 [7]

Answer:

Therefore the equilibrium number of vacancies per unit cubic meter =2.34×10²⁴ vacancies/ mole

Explanation:

The equilibrium number of of vacancies is denoted by N_v.

It is depends on

  • total no. of atomic number(N)
  • energy required for vacancy
  • Boltzmann's constant (k)= 8.62×10⁻⁵ev K⁻¹
  • temperature (T).

N_v=Ne^{-\frac{Q_v}{kT} }

To find  equilibrium number of of vacancies we have find N.

N=\frac{N_A\ \rho}{A_{cu}}

Here ρ= 8.45 g/cm³  =8.45 ×10⁶m³

N_A= Avogadro Number = 6.023×10²³

A_{Cu}= 63.5 g/mole

N=\frac{6.023\times 10^{23}\times 8.45\times 10^{6}}{63.5}

   =8.01\times 10^{28 g/mole

Here Q_v=0.9 ev/atom , T= 1000k

Therefore the equilibrium number of vacancies per unit cubic meter,

N_v=( 8.01\times 10^{28}) e^{-(\frac{0.9}{8.62\times10^{-5}\times 1000})

   =2.34×10²⁴ vacancies/ mole

3 0
3 years ago
A balloon is filled with 3.00 L of helium at a pressure of 765 torr. What is the volume of the balloon at an altitude where the
Sidana [21]

Answer:

4.33L

Explanation:

6 0
3 years ago
Marcus measured the masses and volumes of samples of four different substances, and he calculated their densities. The table sho
Zina [86]

<u>Given:</u>

Calculated density values-

Aluminum = 2.7 g/cm3

Copper = 9.0 g/cm3

Iron = 7.9 g/cm3

Titanium = 4.8 g/cm3

Unknown sample mass = 9.5 g

Sample volume = 2.1 cm3

<u>To determine:</u>

The identity of the unknown sample

<u>Explanation:</u>

'Density' is a physical parameter which can be used to identify the nature of the unknown substance.

Density = Mass/Volume

For the unknown sample

Density = 9.5 g/2.1 cm3 = 4.52 g/cm3

This matches closely with the calculated density of titanium

Ans: The unknown substance is made of titanium

4 0
3 years ago
What volume of carbon dioxide gas at STP is required to produce 456.9g of lithium carbonate?
Margarita [4]

Answer:

It would have to be around 9.8 volume

Explanation:

7 0
3 years ago
Other questions:
  • To what volume will a 2.33 l sample of gas expand if it is heated from 30.0 ∘c to 300.0 ∘c?
    12·1 answer
  • What are the observed results of an experiment that occur from changes in independent variable
    8·1 answer
  • True or false the three types of seismic waves are P eaves, S waves, and T waves
    10·1 answer
  • Gaseous water molecules condense when they _______. Liquid water molecules evaporate when they _______.
    15·1 answer
  • The breakdown of proteins produces:
    8·1 answer
  • A solid is composed entirely of xenon atoms. What type of solid is it?
    10·1 answer
  • 4. The speed of a wave is 75m/s. If the wavelength of the wave is 5m, what is the frequency of the
    15·2 answers
  • What best describes the reactants and products in a reaction at equilibrium?
    15·1 answer
  • Name of 2 elements with their symbols derived from its german name
    15·1 answer
  • If a calm person with a lung capacity of 3.5 liters and a body temperature of 360 C gets angry, what will the volume of the pers
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!