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egoroff_w [7]
4 years ago
6

Consider the first-order reaction described by the equation At a certain temperature, the rate constant for this reaction is 5.8

2 × 10 − 4 s − 1 5.82×10−4 s−1 . Calculate the half-life of cyclopropane at this temperature.
Chemistry
1 answer:
zubka84 [21]4 years ago
8 0

<u>Answer:</u> The half life of the reaction is 1190.7 seconds

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

k = rate constant of the reaction = 5.82\times 10^{-4}s^{-1}

t_{1/2} = half life of the reaction = ?

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{5.82\times 10^{-4}s^{-1}}=1190.7s

Hence, the half life of the reaction is 1190.7 seconds

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