Question

Consider the first-order reaction described by the equation At a certain temperature, the rate constant for this reaction is 5.82 × 10 − 4 s − 1 5.82×10−4 s−1 . Calculate the half-life of cyclopropane at this temperature.

Answer 1

Answer: The half life of the reaction is 1190.7 seconds

Explanation:

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

k = rate constant of the reaction = $5.82\times 10^{-4}s^{-1}$

$t_{1/2}$ = half life of the reaction = ?

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{5.82\times 10^{-4}s^{-1}}=1190.7s$

Hence, the half life of the reaction is 1190.7 seconds