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2 years ago

What volume of a 2.25 M sodium chloride solution will contain 4.58 moles of sodium chloride

Chemistry

1 answer:

Rzqust [24]2 years ago

6 0

Answer:

Option E. 2.04 L

Explanation:

Data obtained from the question include:

Molarity of NaCl = 2.25 M

Mole of NaCl = 4.58 moles

Volume =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. It is represented mathematically as:

Molarity = mole /Volume

With the above formula, we can obtain the volume of the solution as follow:

Molarity = mole /Volume

2.25 = 4.58/volume

Cross multiply

2.25 x volume = 4.58

Divide both side by 2.25

Volume = 4.58/2.25

Volume = 2.04 L

Therefore, the volume of the solution is 2.04 L

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2 years ago

The source of bitterness in dark chocolate is the compound theobromine, an alkaloid present in cocoa beans. In a sample of dark

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Answer: 193 mg of theobromine are present in the sample.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}=\frac{6.45\times 10^{20}}{6.023\times 10^{23}}=1.07\times 10^{-3}moles$

1 mole of theobromine $(C_7H_8N_4O_2)$ weigh = 180 g

$1.07\times 10^{-3}moles$ of theobromine $(C_7H_8N_4O_2)$ weigh = $\frac{180}{1}\times 1.07\times 10^{-3}=0.193g=193mg$ (1g=1000mg)

193 mg of theobromine are present in the sample.

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3 years ago

What are cells made of?

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3 years ago

If 1.20 g of Zn is allowed to react with 2.00 g of CuSO4, according to the equation below, how many grams of Zn will remain afte

sdas [7]

Answer:

After the reaction is complete 0.94 g of Zn are still remaining.

Explanation:

We define the reaction as:

CuSO₄ (aq) + Zn (s) → ZnSO₄ (aq) + Cu(s)

In order to determine the grams of Zn that will remain after the reaction is complete, we need to confirm if the Zn is the limiting reactant.

We determine moles of each reactant:

1.20 g / 65.41 g/mol = 0.0183 moles of Zn

2 g / 159.6 g/mol = 0.0125 moles of sulfate

Ratio is 1:1. 1 mol of sulfate needs 1 mol of Zn to react.

If I have 0.0125 moles of sulfate I will ned the same moles of Zn to complete the reaction.

I have 0.0183 moles, so it is ok that Zn is the reagent in excess

We convert the moles to mass and we make the substraction to answer the grams of Zn that will remain after the reaction:

0.0183 moles . 159.1 g /mol = 2.92 g

0.0125 moles . 159.1 g /mol = 1.98 g

To complete all the reaction we need 2.92 g of sulfate, but I have 1.98 g

After the reaction is complete (2.92 g - 1.98 g) = 0.94 g are still remaining.

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2 years ago

Microwave ovens emit microwave energy with a wavelength of .129 m. What is the energy of exactly one photon of this microwave ra

gayaneshka [121]

λ=Wavelength = .129 m = 0.129 m

E = energy = ?

h =Planck constant = 6.63 × 10^-34 J.s

f = frequency of photo/ electromagnetic radiation = c/λ

c = Speed of light in a vacuum = 3 × 10^8 m/s

___o___o___

$E = hf \\ \\ E = h \frac{c}{λ} \\ \\ E = 6.63 \times {10}^{ - 34} \frac{3 \times {10}^{8} }{0.129} \\ \\ E = \frac{6.63 \times {10}^{ - 34} \times 3 \times {10}^{8} }{0.129} \\ \\ E = \frac{663 \times {10}^{ - 36} \times 3 \times {10}^{8} }{129 \times {10}^{ - 3} } \\ \\E = \frac{1989 \times {10}^{ - 28} }{129 \times {10}^{ - 3} } \\ \\ E = 15.4 \times {10}^{ - 25} J \\ \\ E = 1.54 \times {10}^{ - 24} J$

I hope I helped you^_^

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2 years ago