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Assoli18 [71]
3 years ago
10

What volume of a 2.25 M sodium chloride solution will contain 4.58 moles of sodium chloride

Chemistry
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

Option E. 2.04 L

Explanation:

Data obtained from the question include:

Molarity of NaCl = 2.25 M

Mole of NaCl = 4.58 moles

Volume =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. It is represented mathematically as:

Molarity = mole /Volume

With the above formula, we can obtain the volume of the solution as follow:

Molarity = mole /Volume

2.25 = 4.58/volume

Cross multiply

2.25 x volume = 4.58

Divide both side by 2.25

Volume = 4.58/2.25

Volume = 2.04 L

Therefore, the volume of the solution is 2.04 L

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<h3>Answer:</h3>

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

4.00 g S

<u>Step 2: Identify Conversions</u>

Avogadro's Number

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<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 4.00 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})(\frac{6.022 \cdot 10^{23} \ atoms \ S}{1 \ mol \ S})
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<u>Step 4: Check</u>

<em>Follow sig figs and round. We are given 3 sig figs.</em>

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