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QveST [7]
3 years ago
15

according to newton's first law, massive objects have _____ inertia than small objects, which means it takes more force to move

bigger things than smaller ones.
Physics
2 answers:
vovangra [49]3 years ago
8 0

Answer:

Explanation:

inertia is the property of mass and it directly depends on the magnitude of the mass of the object

So we can say that if the body has larger mass then it must have more inertia

So as we know by the Newton's first law that if there is no unbalanced force on the objector system of mass then there is no change in the state of motion of the object.

So if the state of motion is at rest then the object will remain at rest always while the state of motion is in motion then it will remain in motion

Now if we would like to change the inertia of the object then it require more force for an object with larger inertia

So here we can say

according to newton's first law, massive objects have <u>MORE</u> inertia than small objects, which means it takes more force to move bigger things than smaller ones

Ksenya-84 [330]3 years ago
4 0
According to newton's first law, massive objects have larger inertia than small objects, which means it takes more force to move bigger things than smaller ones.
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A long straight wire carries current to the right of the page. A rectangular loop is positioned directly under the wire in the p
slavikrds [6]

Answer:

Correct option A.

The net force exerted by this loop on the straight wire with the current is directed TOWARDS THE LOOP

Explanation:

The magnetic field exerts a force on a current-carrying wire in a direction given by the right-hand rule 1 (the same direction as that on the individual moving charges). This force can easily be large enough to move the wire since typical currents consist of very large numbers of moving charges.

Given that,

The wire's current is directed towards the right of the page.

The rectangular loops carry current in a clockwise direction.

Since the 'dot' field is increasing hence the induced magnetic field is 'cross', i.e. into the page and by the right-hand rule, the induced current is clockwise.

Then the magnetic field is into the page.

Since was known that

F= iL×B

Note the current is through the wire. Then, the length is in direction of the current.

Note: this equation gives the magnetic force that acts on a length L of a straight wire carrying a current (i) and immersed in a uniform magnetic field (B), that is perpendicular to the wire.

So, the magnetic field is always perpendicular to the current.

So using right hand rule,

F = i(L×B)

The length is to the right i.e. +x direction and the Magnetic field is perpendicular to the plane, i.e. in the +z direction

F = i (L•i × B•k)

F = iLB (i×k)

F = iLB•(-j)

F = -iLB•j

Then, the force is in the negative y-direction i.e. towards the loop.

8 0
4 years ago
A small rubber ball is launched by a compressed-air cannon from ground level with an initial speed of 17.3 m/s directly upward.
elena-s [515]

Answer:

h=15.27m

Explanation:

Since at maximum height the vertical velocity must be null it's better to use the formula:

v_f^2=v_i^2+2ad

We will use this formula for the vertical direction, choosing the upward direction as the positive one, so we have:

0=v_i^2+2ah

or

h=-\frac{v_i^2}{2a}

which for our values is:

h=-\frac{(17.3m/s)^2}{2(-9.8m/s^2)}=15.27m

7 0
3 years ago
You will need to use the Momentum Principle to do the first part of this problem, and the Energy Principle to do the second part
My name is Ann [436]

Answer

given,

Mass of satellite, m = 4500 kg

Mass of the earth, M = 6 x 10²⁴ Kg

Earth circular orbit radius, R = 9.3 x 10⁶ m

a) To find the speed of the satellite

   we need to equate the gravitation force between earth and satellite with the centripetal force.

\dfrac{GMm}{R^2}=\dfrac{mV^2}{R}

V = \sqrt{\dfrac{GM}{R}}

V = \sqrt{\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}}{9.3\times 10^6}}

   V = 6559.89 m/s

b) Minimum amount of energy of satellite

    E = \dfrac{GMm}{r}-\dfrac{1}{2}mv^2

    E =\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}\times 4500}{9.3\times 10^6}}-\dfrac{1}{2}\times 4500\times 6559.89^2

           E = 9.68 x 10¹⁰ J

Minimum amount of energy require to move satellite is equal to E = 9.68 x 10¹⁰ J

3 0
4 years ago
1. Determine the energy released per kilogram of fuel used.
Serga [27]

The formula for energy release per kilogram of fuel burned is energy release per kg=6.702*10-13. and 19. J 1 Mev = 1.602 X 10 T

Calculate the energy in joules per kilogram of reactants given MeV per reaction. Energy is the ability or capacity to perform tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Think of a mole of plutonium-239 (molar mass: 239 grams) as a mole of "reactions."

Energy used in the US per person annually = 3-5 X 1011
Population (number of people) = 3.108The required mass of the fuel is 3.5x1011 x3-1x10 8x 10)/6.703 X1013 kg. the mass required: 1.62 x 1033 kg Mev in Joules 6 is equal to 101.60*I0-
19. J 1 Mev = 1.602 X 10 T, which translates to 1.602*1013/2.39x10-3 energy release per kilogram, or 6.702*10-13.

To learn more about Energy please visit -
brainly.com/question/27671072
#SPJ1

8 0
2 years ago
I need help with this​
zhenek [66]

Answer:

position 1 and 4................

5 0
3 years ago
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