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3 years ago

7

PLEASE HELP DUE IN MINS. Thanks

2 answers:

nika2105 [10]3 years ago

5 0

Answer:

im thinking B, it makes sence i hink, im so sorry if its wrong

Explanation:

rjkz [21]3 years ago

4 0

Answer:

"C" I think....

Explanation:

I am really sorry if I am wrong, but if right, I hope this helps!

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A spring with spring constant 11.5 N/m hangs from the ceiling. A 490 g ball is attached to the spring and allowed to come to res

Natalija [7]

Answer:

The time constant is $\tau = 17.5 \ s$

Explanation:

From the question we are told that

The spring constant is $k = 11.5 \ N/m$

The mass of the ball is $m_b = 490 \ g = 0.49 \ kg$

The amplitude of the oscillation t the beginning is $x = 6.70 cm = 0.067 \ m$

The amplitude after time t is $x_t = 2.20 cm = 0.022 \ m$

The number of oscillation is $N = 30$

Generally the time taken to attain the second amplitude is mathematically represented as

$t = N * T$ Here T is the period of oscillation

$t = N * 2\pi \sqrt{\frac{m}{k} }$

=> $t = 30 * 2 * 3.142 * \sqrt{\frac{ 0.490}{11.5} }$

=> $t = 38.88 \ s$

Generally the amplitude at time t is mathematically represented as

$x(t) = x e^{-\frac{at}{2m} }$

Here a is the damping constant so

at $t = 38.88 \ s$ , $x_t = 2.20 cm = 0.022 \ m$

So

$0.022 = 0.067 e^{-\frac{a * 38.88}{2 * 0.490} }$

=> $0.3284 = e^{-\frac{a * 38.88}{2 * 0.490} }$

taking natural log of both sides

=> $ln(0.3284 ) = -\frac{a * 38.88}{2 * 0.490} }$

=> $a = 0.028$

Generally the time constant is mathematically represented as

$\tau = \frac{m}{a}$

=> $\tau = \frac{0.490}{ 0.028}$

=> $\tau = 17.5 \ s$

4 0

3 years ago

Which sphere of Earth do humans exist in?

PolarNik [594]

Biosphere is the answer, hope i helped :))

4 0

3 years ago

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A sphere is charged with electrons to -6 x 10^-6C. How many electrons make up this charge? The elemental charge is 1.6 x 10^-19

just olya [345]

Answer:

$3.75*10^{-13}$ electrons

Explanation:

The total charge Q is the sum of the charge of the N electrons contained in the sphere:

$Q=N*q_{e}$

$q_{e}=-1.6*10^{-19}C$ charge of a electron

We solve to find N:

$N=\frac{Q}{q_{e}}=\frac{-6 x 10^{-6}}{-1.6 x 10^{-19}}=3.75*10^{-13}$

7 0

4 years ago

A bird with a mass of 0.88 kg has a potential energy of 96 J. How high off the ground is the bird?

Ray Of Light [21]

Answer:

Data:-m=0.88kg ,g=9.8m/sec² ,P.E=96J ,h=?

Explanation:

solution ,P.E=mgh here we have to find h so h=P.E/mg ,h=96/0.88×9.8 ,h=96/8.624=11.131m and if you want to verify so just put the value of h in same formula, likewise :-P.E=mgh ,P.E=0.88×9.8×11.131=96J so we got the same value of P.E as it is given the question (verified).

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3 years ago

2+2 can someone plz tell me the pros and cons of ending life right here and now?

kari74 [83]

2+2=4, thx for the pts

8 0

3 years ago

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