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3 years ago

The amount of energy required to raise the temperature of a swimming pool depends on the mass of water present.

Chemistry

1 answer:

cluponka [151]3 years ago

3 0

True. Refer to the heat equation of water

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Consider the reaction between a solution of molecule A and a solid block of molecule B. In general, for a reaction to occur, the

Blababa [14]

Answer:

Decreasing the volume of solvent in the solution of molecule A

Explanation:

We know that one of the factors that affect the rate of reaction is the concentration of the reactants. The greater the concentration of reactants, the faster the rate of reaction (the greater the frequency of collision between reactants).

Hence, when we decrease the volume of solvent in the solution of molecule A, the concentration of the solution increases and consequently more particles of molecule A are available to collide with particles of molecule B resulting in a higher rate of reaction.

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2 years ago

At what temperature would a 1.50 m nacl solution freeze, given that the van't hoff factor for nacl is 1.9? kf for water is 1.86

IRINA_888 [86]

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2 years ago

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MA_775_DIABLO [31]

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2 years ago

What does velocity describe

White raven [17]

Velocity describes the speed of an object and its direction of motion

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3 years ago

Read 2 more answers

HELP!!!! The freezing of methane is an exothermic change. What best describes the temperature conditions that are likely to make

vazorg [7]

Answer: The correct statement is low temperature only, because entropy decreases during freezing.

Explanation:

The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:

$\Delta G=\Delta H-T\Delta S$

Where,

$\Delta G$ = change in Gibb's free energy

$\Delta H$ = change in enthalpy

T = temperature

$\Delta S$ = change in entropy

It is given that freezing of methane is taking place, which means that entropy is decreasing and $Delta S$ is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the $\Delta H$ is also negative.

For a reaction to be spontaneous, $\Delta G$ must be negative.

$-ve=-ve-[T(-ve)]\\\\-ve=-ve+T$

From above equations, it is visible that $\Delta G$ will be negative only when the temperature will be low.

Hence, the correct statement is low temperature only, because entropy decreases during freezing.

8 0

3 years ago