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3 years ago

Which of the following is a double replacement reaction?

Chemistry

1 answer:

Gekata [30.6K]3 years ago

7 0

Answer:

The answer to your question is: letter D.

Explanation:

Double replacement reaction is when the cation of one reactant replaces the metal of the other reactant and vice versa.

a. 2SO2 + O2 —> 2S03 This is a combination reaction

b. Zn + Cu(NO3)2 → Zn(NO3)2 + Cu This is a single replacement reaction.

c. 2H2O2–> 2H2O + O2 This is a decomposition reaction

d . AgNO3 + NaCl → AgCl + NaNO3 This is a double replacement reaction

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Cyclobutane simplified structural formula please

daser333 [38]

Answer:

Cyclobutane is a cycloalkane and organic compound with the formula (CH2)4.

Explanation:

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3 years ago

answer now please Which device can be used to separate nails from sawdust most efficiently? A. strainer B. magnet C. colander D.

e-lub [12.9K]

A magnet because it will remove only metal and not the saw dust

Hope this helps

6 0

3 years ago

Read 2 more answers

Describe how particles of iron (Fe) an oxygen (O2) react to how produce oxide (Fe2O3), also known as rust.

forsale [732]

Answer:

Described by a redox reaction below

Explanation:

Iron(III) oxide is an ionic compound, since it consists of a metal, iron, and a nonmetal, oxygen.

Ionic compounds are formed when metals lose their valence electrons in order to have an octet in their previous shell and donate them to nonmetal atoms, so that nonmetals fill their outer shell to have an octet.

As a result, positive ions (cations) and negative ions (anions) are formed. When iron reacts with oxygen, the following reaction takes place:

$4 Fe (s) + 3 O_2 (g)\rightarrow 2 Fe_2O_3 (s)$

This is a redox (oxidation–reduction) reaction, since we have electron loss and gain. Four iron atoms lose a total of 12 electrons to obtain a +3 charge in the final compound, while 3 oxygen molecules gain these 12 electrons to become 6 oxide anions with a -2 charge.

4 0

3 years ago

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AnnyKZ [126]

Answer:

Already answered brainly.com/question/845321563

Explanation:

8 0

3 years ago

What volume (in mL) of a 0.200 MHNO3 solution is required to completely react with 27.6 mL of a 0.100 MNa2CO3 solution according

ladessa [460]

Answer:

There is 27.6 mL of a 0.200 M HNO3 solution required

Explanation:

Step 1: The balanced equation is:

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

This means for 1 mole Na2CO3 consumed, there is consumed 2 mole of HNO3 and there is produced 2 moles of NaNO3, 1 mole of CO2 and 1 mole of H2O

Step 2: Calculating moles of Na2CO3

moles of Na2CO3 =volume of Na2CO3 * Molarity of Na2CO3

moles of Na2CO3 = 27.6 *10^-3 * 0.1 M = 0.00276 moles

Step 3: Calculating moles of HNO3

In the balanced equation, we can see that for 1 mole of Na2CO3 consumed, there are consumed 2 moles of HNO3.

So for 0.00276 moles consumed of Na2CO3, there are consumed 0.00552 moles of HNO3.

This means 0.00276 moles of the base Na2CO3 would react with 0.00552 moles of the acid HNO3

Step 4: Calculating the volume of HNO3

volume of HNO3 = moles of HNO3 / Molarity of HNO3

volume of HNO3 = 0.00552 moles / 0.200 M = 0.0276 L

0.0276 L = 27.6 ml

There is 27.6 mL of a 0.200 M HNO3 solution required

4 0

3 years ago