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Lelu [443]
3 years ago
15

What is not true about most combustion reactions? a) elemental carbon is a product b) energy is released c) a carbon-based fuel

is a reactant d) molecular oxygen is a reactant
Chemistry
2 answers:
White raven [17]3 years ago
8 0

It would be A bc carbon is NOT usually a product. You can find out more about the by searching combustion reactions, then u should be able to answer the questions on your own.

Brums [2.3K]3 years ago
4 0

<u>Answer:</u> The correct answer is Option a.

<u>Explanation:</u>

Combustion reaction is defined as the reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule. It is considered as an exothermic reaction as energy is released during these reactions.

A hydrocarbon is a substance which contains a covalent bond between a hydrogen and carbon atoms. So, it is considered as a carbon-fuel compound.

The general equation for this reaction follows:

\text{hydrocarbon}+O_2(g)\rightarrow CO_2(g)+H_2O(g)+\text{heat}

From the above equation, it is visible that elemental carbon is not produced.

Hence, the correct answer is Option a.

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_______ law states the volume of a definite quantity of dry gas is inversely proportional to the pressure, provided the temperat
nasty-shy [4]
Boyles law --i hope this helps
5 0
3 years ago
From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp
Nina [5.8K]

<u>Answer:</u> The concentration of NH_3 required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of NiC_2O_4, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles of NiC_2O_4 = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M

For the given chemical equations:

NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}

Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9

Net equation: NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?

To calculate the equilibrium constant, K for above equation, we get:

K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48

The expression for equilibrium constant of above equation is:

K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}

As, NiC_2O_4 is a solid, so its activity is taken as 1 and so for C_2O_4^{2-}

We are given:

[[Ni(NH_3)_6]^{2+}]=0.016M

Putting values in above equations, we get:

0.48=\frac{0.016}{[NH_3]^6}}

[NH_3]=0.285M

Hence, the concentration of NH_3 required will be 0.285 M.

7 0
3 years ago
What volume is used to calculate the volume of a solid object ​
Degger [83]

Answer:

cubic measurements

Explanation:

i.e. cubic meter or cubic centimeter

3 0
3 years ago
Does the sound wave above experience a change in pitch or loudness? Why?
Basile [38]

My Apoligies for not being sooner.

Answer: The closer the particles get or the further apart they get, the greater the sound's amplitude. Sound amplitude causes a sound's loudness and intensity. The bigger the amplitude is, the louder and more intense the sound. - (This is copied)

General Answer : Its a change in sound, bassically the bigger the waves are, the louder the sound is.

4 0
2 years ago
A pure copper penny contains approximately 2.9×1022 copper atoms. Use the following definitions to determine how many ______ of
hammer [34]

Complete question is;

A pure copper penny contains approximately 2.9 × 10^(22) copper atoms.

1 doz = 12

1 gross = 144

1 ream = 500

1 mol = 6.022 × 10^(23)

Use these definitions to determine the following:

A) How many dozens of copper atoms are in a penny.

B) How many gross of copper atoms are in a penny

C) How many reams of copper atoms are in a penny.

D) how many moles of copper atoms are in a penny?

All answers can be rounded to two significant figures

Answer:

A) 2.4 × 10^(21) dozens

B) 2.01 × 10^(20) gross

C) 5.8 × 10^(19) reams

D) 0.048 mol

Explanation:

A) A dozen contains 12.

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/12 dozens = 2.42 × 10^(21).

In 2 significant figures, we have;

2.4 × 10^(21) dozens

B) 1 gross = 144

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/144 gross ≈ 2.01 × 10^(20) gross

C) 1 ream = 500

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/500 reams = 5.8 × 10^(19) reams

D) 1 mol = 6.022 × 10^(23)

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/(6.022 × 10^(23)) = 0.048 mol

6 0
3 years ago
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