Answer:
r = 3.61x
M/s
Explanation:
The rate of disappearance (r) is given by the multiplication of the concentrations of the reagents, each one raised of the coefficient of the reaction.
r = k.![[S2O2^{-8} ]^{x} x [I^{-} ]^{y}](https://tex.z-dn.net/?f=%5BS2O2%5E%7B-8%7D%20%5D%5E%7Bx%7D%20x%20%5BI%5E%7B-%7D%20%5D%5E%7By%7D)
K is the constant of the reaction, and doesn't depends on the concentrations. First, let's find the coefficients x and y. Let's use the first and the second experiments, and lets divide 1º by 2º :



x = 1
Now, to find the coefficient y let's do the same for the experiments 1 and 3:




y = 1
Now, we need to calculate the constant k in whatever experiment. Using the first :


k = 4.01x10^{-3} M^{-1}s^{-1}[/tex]
Using the data given,
r = 
r = 3.61x
M/s
The answer to this question would be: decrease
If the process is releasing heat to the surrounding, that means it should be an exothermic process. In the exothermic process, the process enthalpy difference will be minus because some of the energy is released as heat. That means the enthalpy of the system will be decreased.
An outline is a line drawn around an element, enclosing the element content, padding, and border spaces.
A form or figure's outline is defined by a line or combination of lines. The lines restrict the shape, isolating it inside the composition or the area. The shapes are created by the outlines.
The phrase "outline" in art refers to the lines, real or apparent, that define or confine a figure (or shape) within the field of vision, with the total number of these lines defining the contour of the figure.
An item is depicted by lines of contour without shade in an outline sketch or drawing, leaving out internal detail. A variety of markers are used to transform an object's seeming edge into a useful reference on paper.
To learn more about drawing refer to:
brainly.com/question/12100213
#SPJ4
Okay then- uhm mark me brainliest?