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3 years ago

1. Calculate the average atomic mass of iron if its abundance in nature is 15%-iron-55 and

Chemistry

1 answer:

blsea [12.9K]3 years ago

8 0

The average atomic mass of iron : 55.85 amu

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

An atomic mass unit = amu is a r<em>elative atomic mass of 1/12 the mass of an atom of carbon-12. </em>

The 'amu' unit has now been replaced with a unit of 'u' only

Atomic mass is the average atomic mass of all its isotopes

atomic mass X = mass isotope 1 . % + mass isotope 2.% ...

The average atomic mass of iron

$\tt =0.15\times 55+0.85\times 56\\\\=\boxed{\bold{55.85~amu}}$

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AB → A + B

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Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

$\frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} )$ ,

where λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from $n_1$ to $n_2$ and $R_h$ = 109677 is the Rydberg Constant. Here $n_1$ and $n_2$ represents the transitions.

(a) $n_1$ =2 to $n_2$ = infinity

$\frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2} )$ = 109677/4 [since 1/infinity = 0] Therefore, $\lambda$ = 4 / 109677 = 0.00003647 m

(b) $n_1$ =4 to $n_2$ = 20

$\frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2} )$ = 6580.62

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(c) $n_1$ =3 to $n_2$ = 10

$\frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2} )$ = 11089.56

Therefore, $\lambda$ = 1 / 11089.56 = 0.00009 m

(d) $n_1$ =2 to $n_2$ = 1

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Therefore, $\lambda$ = 1 /82257.75 = - 0.0000121 m

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

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here is ur ans Lilly

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hope it's helpful for you mark brainlest where you from , age

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