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3 years ago

How many Joules does it take to heat up 15.1 kg of glass from 15°C to 45°C

Chemistry

1 answer:

Vedmedyk [2.9K]3 years ago

6 0

<h3>Answer:</h3>

380,520 Joules

<h3>Explanation:</h3>

Quantity of heat,Q is calculated by multiplying the mass, m of a substance by specific heat capacity, c of the substances and the change in temperature, Δt.

That is;

Q = m×c×Δt

In the question above;

Mass of glass is 15.1 kg

Change in temperature = 45°C - 15 °C

= 30°C

Specific heat capacity of glass = 840 J/kg/°C

Therefore;

Quantity of heat, Q = 15.1 kg × 840 J/kg/°C × 30°C

= 380,520 Joules

Hence, it takes 380,520 Joules to heat up 15.1 kg of glass from 15°C to 45°C.

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Answer:

Explanation:

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The following equilibrium is formed when copper and bromide ions are placed in a solution:

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Answer:

1. Reaction will shift rightwards towards the products.

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Explanation:

Hello,

In this case, for the stated equilibrium:

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In such a way, by thinking out the Le Chatelier's principle, we can answer to each question:

1. If potassium bromide, which adds bromide ions, is added more reactant is being added to the solution, therefore, the reaction will shift rightwards towards the products.

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2 years ago

How many Hydrogen atoms are in 4HN₃?

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1 year ago

The rate constant for the reaction 3A equals 4b is 6.00×10 how long will it take the concentration of a to drop from 0.75 to 0.2

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This question is incomplete, the complete question is;

The rate constant for the reaction 3A equals 4B is 6.00 × 10⁻³ L.mol⁻¹min⁻¹.

how long will it take the concentration of A to drop from 0.75 to 0.25M ?

from the unit of the rate constant we know it is a second reaction order

OPTIONS

a) 2.2×10^−3 min

b) 5.5×10^−3 min

c) 180 min

d) 440 min

e) 5.0×10^2 min

Answer:

it will take 440 min for the concentration of A to drop from 0.75 to 0.25M

Option d) 440 min is the correct answer

Explanation:

Given that;

Rate constant K = 6.00 × 10⁻³ L.mol⁻¹min⁻¹

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given that it is a second reaction order;

k = 1/t [ 1/A - 1/A₀]

kt = [ 1/A - 1/A₀]

t = [ 1/A - 1/A₀] / k

K is the rate constant(6.00 × 10⁻³)

A₀ is initial concentration( 0.75 )

A is final concentration(0.25)

t is time required = ?

so we substitute our values into the equation

t = [ (1/0.25) - (1/0.75)] / (6.00 × 10⁻³)

t = 2.6666 / (6.00 × 10⁻³)

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Option d) 440 min is the correct answer

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