(a) the weight of the fish is:

and this is the force that stretches the spring by

. So, we can use Hook's law to find the constant of the spring:

(b) The fish is pulled down by 2.8 cm = 0.028 m more, so now the total stretch of the spring is

But this is also the amplitude of the new oscillation, because this is the maximum extension the spring can get, so A=6.5 cm.
The angular frequency of oscillation is given by:

and so the frequency is given by
Answer:
Final volume, V2 = 24.62 L
Explanation:
Given the following data;
Initial volume = 40 L
Initial pressure = 80 Pa
Final pressure = 130 Pa
To find the final volume V2, we would use Boyles' law.
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
Substituting into the equation, we have;




Final volume, V2 = 24.62 Liters
Answer:
TRUE
Explanation:
Low mass stars last lots longer.
Answer:
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Answer:
Incomplete question, check attachment for completed question
Explanation:
The force of attraction between two forces are given as
F=kQq/r²