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Marysya12 [62]
3 years ago
7

Why scientifically died it hurt when you stub your toe in the corner of a wall?

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
Each digit has two nerves, one on either side,” Dr. Botek says. “So no matter where you hit your toe or how you stub it, it’s going to affect a nerve impulse from your toe to your brain.”
This nerve impulse is modulated by sensory neurons called nociceptors, which fire off information to the brain whenever they sense an external stimulus that may cause harm to the body. That includes extreme heat or cold, certain chemicals that could burn the skin, or mechanical pressure that could damage the tissue (like the force involved when you bang a toe into the hard foot of a chair, for instance).
“When that specialized neuron gets activated, it fires, sending that information to the spinal cord,” Jeffrey Mogil, Ph.D., a neuroscientist and professor of pain studies at McGill University, tells SELF. From there, the information is processed by the brain and, eventually, you perceive it as pain.
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Physics is defined as:
nikitadnepr [17]

Answer:

B. Developed out of efforts of man trying to explain our physical environment.

Explanation:

This is because physics, as we all know of, is considered to be <em>crucial to understanding the world around us</em>, making it the most basic and fundamental of science.

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3 years ago
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outward from a wall just above floor level. A 1.5 kg box sliding across a frictionless floor hits the end of the spring and comp
sweet [91]

Answer:

v = 0.489 m/s

Explanation:

It is given that,

Mass of a box, m = 1.5 kg

The compression in the spring, x = 6.5 cm = 0.065 m

Let the spring constant of the spring is 85 N/m

We need to find the velocity of the box (v) when it hit the spring. It is based on the conservation of energy. The kinetic energy of spring before collision is equal to the spring energy after compression i.e.

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

v=\sqrt{\dfrac{kx^2}{m}} \\\\v=\sqrt{\dfrac{85\times (0.065)^2}{1.5}} \\\\v=0.489\ m/s

So, the speed of the box is 0.489 m/s.

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3 years ago
Estimate the radiation pressure due to a bulb that emits 25 W of EM radiation at a distance of 6.5 cm from the center of the bul
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..........................................................

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2 years ago
A healthy environment depends on biogeochemical cycles maintaining a balance of input and output. When forests are cut down, whi
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The correct answer will be c
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2 years ago
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A ball is attached to a string of length 3 m to make a pendulum. The pendulum is placed at a location that is away from the Eart
Musya8 [376]

1) 0.61 m/s^2

2) 13.9 s

Explanation:

1)

The acceleration due to gravity is the acceleration that an object in free fall (acted upon the force of gravity only) would have.

It can be calculated using the equation:

g=\frac{GM}{r^2} (1)

where

G is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

r is the distance of the object from the Earth's center

The pendulum in the problem is at an altitude of 3 times the radius of the Earth (R), so its distance from the Earth's center is

r=4R

where

R=6.37\cdot 10^6 m is the Earth's radius

Therefore, we can calculate the acceleration due to gravity at that height using eq.(1):

g=\frac{GM}{(4R)^2}=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})0.}{(4\cdot 6.37\cdot 10^6)^2}=0.61 m/s^2

2)

The period of a simple pendulum is the time the pendulum takes to complete one oscillation. It is given by the formula

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration due to gravity at the location of the pendulum

Note that the period of a pendulum does not depend on its mass.

For the pendulum in this problem, we have:

L = 3 m is its length

g=0.61 m/s^2 is the acceleration due to gravity (calculated in part 1)

Therefore, the period of the pendulum is:

T=2\pi \sqrt{\frac{3}{0.61}}=13.9 s

4 0
3 years ago
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