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ololo11 [35]
4 years ago
15

A net force of 25.0 N causes an object to accelerate at 4.00 m/s2. What is the mass of the object?

Physics
2 answers:
maxonik [38]4 years ago
3 0

Answer:

6.25kg

Explanation:

m=F/a = 25/4 = 6.25kg

defon4 years ago
3 0

Answer:

Mass, m = 6.25 kg

Explanation:

It is given that,

Net force acting on the object, F = 25 N

Acceleration of the object, a=4\ m/s^2

Let m is the mass of the object. Using Newton's second law of motion. The force is given by :

F = ma

m=\dfrac{F}{a}

m=\dfrac{25\ N}{4\ m/s^2}

m = 6.25 kg

So, the mass of the object is 6.25 kg. Hence, this is the required solution.

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A proton traveling due north enters a region that contains both a magnetic field and an electric field. The electric field lines
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Two cars are moving in the same direction at the same speed of (72.0 kmh). What is
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Answer:

0 km/h

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Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.
alexandr1967 [171]

Answer:

v=\sqrt{k\frac{e^2}{m_e r}}, 2.18\cdot 10^6 m/s

Explanation:

The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

r is the distance between the electron and the nucleus

v is the speed of the electron

m_e is the mass of the electron

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v=\sqrt{k\frac{e^2}{m_e r}}

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

r=5.3\cdot 10^{-11}m

while the electron mass is

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e=1.6\cdot 10^{-19} C

Substituting into the formula, we find

v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s

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