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dimaraw [331]
3 years ago
8

Suppose you are standing on a bathroom scale when you are flying in a jet airplane. for a moment the scale reads less than your

actual weight. during that moment, it's exerting an upward force on you that is
Physics
1 answer:
IRINA_888 [86]3 years ago
7 0

Answer:

Inertia

Explanation:

When the planes moves downward a speed, the weight of the person will decrease a bit due to the amount of g decreases for that particular instant. The person is now experiencing a less than actual weight called as apparent weight due to the upward superposition of inertia on the body as we can see in w = m g .

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When divided by △t, (vf - vi) is used to determine which characteristic? A.Speed B.Direction C. Displacement D.Acceleration
Keith_Richards [23]

Answer:

D.Acceleration

Explanation:

The acceleration of an object is defined as:

a=\frac{v_f -v_i}{\Delta t}

where

vf is the final velocity of the object

vi is the initial velocity of the object

\Delta t is the time taken for the change in velocity to occur

Therefore, from the formula, we see that if we divide (vf - vi)  by △t, we get the acceleration.

6 0
3 years ago
If a car with a mass of 1,200 kg traveling westward at 30 m/s is
forsale [732]

The net force acting on the car is equal to -12000 Newton.

<u>Given the following data:</u>

  • Mass = 1,200 kg
  • Initial velocity = 30 m/s.
  • Final velocity = 0 m/s (since the car came to a stop).
  • Time = 3 seconds.

To determine the net force acting on the car:

<h3>How to calculate the net force.</h3>

Mathematically, the net force acting on the car is given by Newton's Second Law of Motion:

F = \frac{m(v\;-\;u)}{t}

<u>Where:</u>

  • m is the mass.
  • t is the time.
  • u is the initial velocity.
  • u is the final velocity.

Substituting the given parameters into the formula, we have;

F = \frac{1200 \times (0\;-\;30)}{3}\\\\F = \frac{1200 \times (-30)}{3}\\\\F = \frac{-36000 }{3}

Net force = -12000 Newton.

Read more on net force here: brainly.com/question/1121817

5 0
2 years ago
When the electron in a hydrogen atom moves from n = 6 to n = 1, light with a wavelength of ________ nm is emitted?
Oduvanchick [21]
First we find the energy level with the following formula, where a is the energy level, n1 is the final energy level, n2 is the starting energy level and r is Rydberg's constant in Joules
a = r \times ( \frac{1}{n1}  -  \frac{1}{n2} )
We insert the values

a = 2.18 \times  {10}^{ - 18}  \times ( \frac{1}{ {1}^{2} } -  \frac{1}{ {6}^{2} }  )
= 2.12 \times {10}^{ - 18}
The wavelength is found with this formula, where h is Planck's constant and c is the speed of light
wavelength =  \frac{h \times c}{a}
Finally we insert the values
\frac{6.626 \times  {10}^{ - 34}  \times 3 \times  {10}^{8} }{2.12 \times  {10}^{ - 18} }  = 9.376 \times  {10}^{ - 8}
Which is the same as 93.8 nm
3 0
3 years ago
What is the self-inductance of a solenoid 30.0 cm long having 100 turns of wire and a cross-sectional area of 1.00 × 10-4 m2? (μ
madreJ [45]

Answer:

L=4.19*10^{-6}H

Explanation:

The self-inductance of a solenoid is defined as:

L=\frac{\mu N^2A}{l}

Here \mu_0 is the the permeability of free space, N is the number of turns in the solenoid, A is the cross-sectional area os the solenoid and l its length. We replace the given values to get the self-inductance:

L=\frac{4\pi*10^{-7}\frac{T\cdot m}{A}(100)^2(1*10^{-4}m^2)}{30*10^{-2}m}\\L=4.19*10^{-6}H

4 0
4 years ago
The Hubble Space Telescope was released from the Space Shuttle, which was in a circular orbit at 400km earth altitude. The relat
snow_lady [41]

Answer:

d = (75 i ^ + 93 j ^ + 27 k ^) m ,  d2 = (900 i ^ + 1116 j ^ + 324 k ^) m

Explanation:

The two objects are in circular orbit together, therefore with the same angular velocity, after the launch they move with the relative velocity, so we can use the kinematic relation

       

         v = d / t

         d = v t

Reduce time to units SI

         t = 5 min (60 s / 1 min) = 300 s

X axis

         x = vₓ t

         x = 0.25 300

         x = 75 m

Y axis  

        y = v_{y} t

        y = 0.31 300

       y = 93 m

Z axis

        z=  v_{z} t

        z = 0.09 300

       z = 27 m

       d = (75 i ^ + 93 j ^ + 27 k ^) m

For the time of 1 h

       t2 = 1 h (3600s / 1 h) = 3600

       x2 = 900 m

       y2 = 1116 m

       z2 = 324 m

      d2 = (900 i ^ + 1116 j ^ + 324 k ^) m

5 0
4 years ago
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