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3 years ago

You walk out to the edge of a 2,384 m. cliff and you toss a rock down to watch it drop. What is the rocks acceleration?

Physics

1 answer:

likoan [24]3 years ago

3 0

Answer:

9.8m/s

Explanation:

Wherever you're on the earth's surface, gravitational force remains the same and it does not matter either its a rock that's being tossed or a sheet of paper, the acceleration remains 9.8m/s only. *Condition applied=air resistance neglected

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The speed of a wave with a frequency of 2 Hz (2/s), an amplitude of 3 m, and a wavelength of 10 m is

Inessa05 [86]

Answer:

5 m/s

Explanation:

your welcome

6 0

2 years ago

Taking the resistivity of platinoid as 3.3 x 10-7 m, find the resistance of 7.0 m of platinoid wire of average diameter 0.14 cm.

mr_godi [17]

Answer:

$1.5 \Omega$

Explanation:

The resistance of a wire is given by the equation:

$R=\rho \frac{L}{A}$

where

$\rho$ is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

In this problem, we have a wire of platinoid, whose resistivity is

$\rho = 3.3\cdot 10^{-7} \Omega m$

The length of the wire is

L = 7.0 m

And its radius is

$r=\frac{0.14 cm}{2}=0.07 cm = 7\cdot 10^{-4} m$ , so the cross-sectional area is

$A=\pi r^2=\pi(7\cdot 10^{-4})^2=1.54\cdot 10^{-6}m^2$

Solving for R, we find the resistance of the wire:

$R=(3.3\cdot 10^{-7})\frac{7.0}{1.54\cdot 10^{-6}}=1.5 \Omega$

3 0

2 years ago

Holden is trying to turn man the velocity of his car, he went 20 meters east, turned around and left 40 meters less, he turned t

Grace [21]

Answer:

3 m/s east

Explanation:

The velocity of the car is given by:

$v=\frac{d}{t}$

where

d is the displacement

t is the time taken

The displacement of the car does not depend on the path of the car, but just on it the difference between its final position and its starting position, so it is equal to 15 metres east. The time taken is 5 seconds, therefore the velocity is equal to

$v=\frac{15 m}{5 s}=3 m/s$

and the direction is east.

4 0

3 years ago

Explain what happens inside the radiation zone that causes the photon to take so long to exit the sun

DaniilM [7]

-A photon travels, on average, a particular distance, d, before being briefly absorbed and released by an atom, which scatters it in a new random direction.

-Given d and the speed of light, c, you can figure out the average time step and space step size (how often the photon “steps” and how far it “steps” each time).

-The size of the Sun is figured in terms of step size. Some surprisingly tricky math happens, involving “Brownian motion” and probabilities. Finally,

-The average time it would take to get to the surface of the Sun is found.

6 0

2 years ago

A 1500-kg car accelerates from rest to 25 m/s in 7.0 s. what is the average power delivered by the engine? (1 hp = 746 w)

AVprozaik [17]

The solution for this is:
Work done = force * distance = m*a*d and power = energy/time
The vo=0 and vf = 25 m/s and t=7 sec. This gives...
3.6 m/s^2 as acceleration and d=87.5 meters and thus F=ma= 5400 N.
Energy = 5400*87.5 = 4.7E5 Joules (2 sig. figs) and Power = 67,500 Watts or 90 HP (2 sig. figs again).

5 0

3 years ago

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