Answer:
The solution to this question is as follows
Hence the x component of the initial velocity of the Chinook salmon is 2 m/s
The y component of the initial velocity of the salmon to scale the waterfall is 5.3 m/s
see explanation below
Explanation:
To solve this question, we need to list out the known values from where the number of unknowns and the right equation of motion can be decided thus;
Height of the waterfall = 1.43m
Distance of the fish from the base of the ledge over which the water fall flows = 1.08m
Thus the equations of motion required include
v² = u² - 2×g×S and
v = u -g×t
where u is the the initial velocity we have
v = 0 for vertical velocity at the top of the ledge
thus u = gt at the top of the ledge and S = 1.43m
this gives (gt)²-2×1.43×g =0 or
2.86 =gt² or t² = 2.86÷9.81 = 0.29 or t = 0.54s
From where the vertical component of the velocity = 9.81×0.54 = 5.3m/s
similarly the horizontal component can be found by v = distance÷time
= (horizontal distance from the bottom of the ledge) ÷ (the time it takes to scale the ledge) = 1.08÷0.54 = 2 m/s
Hence the x component of the initial velocity of the Chinook salmon is 2 m/s
The y component of the initial velocity of the salmon to scale the waterfall is 5.3 m/s
