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Andrei [34K]
3 years ago
15

How do you calculate mass using density and volume??

Chemistry
1 answer:
LiRa [457]3 years ago
8 0
Just reorder the equation

Density= mass/volume
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List two processes from which it may be concluded that the particles of a gas move continuously.
ziro4ka [17]

Answer:

The two processes maybe:

  • One process can be the spread of smell of perfume . Tge particles of perfume mic in the air and reaches every corner of tge room because they are moving

  • Second can be the smell of food that reaches us in seconds . This case too tells that the aroma of the food particles gets intermixed and come to us .
5 0
4 years ago
A fruit-and-oatmeal bar contains 142 nutritional Calories. Convert this energy to calories
madreJ [45]

Answer:

a fruit and oatmeal bar contains 142000 calories.

A nutritional calorie, or kilocalorie, is equal to 1000 calories.

E = 142 kcal · 1000 cal/kcal.

E = 142 000 cal.

Calorie (cal), or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.

One small calorie is approximately 4.2 joules.

A calorie is a unit of energy.

Explanation:

hope it helps  :)

4 0
3 years ago
If you start with 4.5 moles of aluminum and 6.5 moles of copper chloride to make aluminum chloride and copper, what is the limit
Alex Ar [27]

Answer:

The limiting reagent is CuCl

Explanation:

The initial number of moles of aluminum, Al = 4.5 moles

The number of moles of copper, Cu = 6.5 moles

The given chemical reaction is presented as follows;

2Al + 3CuCl → 2AlCl₃ + 3Cu

Therefore, we have, 2 moles of aluminum combine with 3 moles of CuCl produces 2 moles of AlCl₃ and 3 moles of Cu

1 mole of Al will combine with (3/2) moles of CuCl,

Therefore, 4.5 moles of Al will combine with (4.5 × (3/2) = 6.75) 6.75 moles of CuCl

Given that the number of moles of CuCl present is only 6.5 moles which is less than the 6.75 moles required to combine with the 4.5 moles, the 6.5 moles of CuCl limits the amount of AlCl₃ and Cu produced, and therefore the CuCl is the limiting reagent.

8 0
3 years ago
Someone answer the limited regent...
OleMash [197]

Answer:

20 g Ag

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Using Dimensional Analysis

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table

Explanation:

<u>Step 1: Define</u>

[RxN]   Cu (s) + AgNO₃ (aq) → CuNO₃ (aq) + Ag (s)

[Given]   10 g Cu

<u>Step 2: Identify Conversions</u>

[RxN]   1 mol Cu = 1 mol Ag

Molar Mass of Cu - 63.55 g/mol

Molar Mass of Ag - 197.87 g/mol

<u>Step 3: Stoichiometry</u>

<u />10 \ g \ Cu(\frac{1 \ mol \ Cu}{63.55 \ g \ Cu})(\frac{1 \ mol \ Ag}{1 \ mol \ Cu} )(\frac{197.87 \ g \ Ag}{1 \ mol \ Ag} ) = 16.974 g Ag

<u>Step 4: Check</u>

<em>We are given 1 sig fig. Follow sig fig rules and round.</em>

16.974 g Ag ≈ 20 g Ag

6 0
3 years ago
Examine the graph to determine half life of strontium -90
s344n2d4d5 [400]
25 years! Note that it takes 25 years for half of strontium 90 to decay.
8 0
3 years ago
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