The required mole ratio of NH₃ to N₂ in the given chemical reaction is 2:4.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.
Given chemical reaction is:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
From the stoichiometry of the reaction it is clear that:
4 moles of NH₃ = produces 2 moles of N₂
Mole ratio NH₃ to N₂ is 2:4.
Hence required mole ratio is 2:4.
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The concentration of hydrogen ions in a solution is a measure of its acidity. So the correct option is (b) false.
When an Arrhenius acid is dissolved in water, hydrogen ions are produced:
H+(aq) + A- = HA + H2O (aq)
Here, H+ is the hydrogen cation, A- is the solvated anion, also known as the conjugate base, and HA is the non-dissociated acid. When an Arrhenius base is dissolved in water, hydroxide ions are produced:
BOH + H2O → B+(aq) + OH-(aq)
Is a material with at least one hydrogen atom that has the ability to split apart in an aqueous solution to produce an anion and an H + ion (a proton), creating an acidic solution. Bases are substances that, when dissolved in water, create hydroxide ions (OH) and a cation, resulting in a basic solution.
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Answer:
Sulphur
Explanation:
Sulphur because we been 2 ag for 1 s therefore 0.312 S will need 0.624 of Ag
Answer:
no matter is destroyed or created, it merely changes form. In terms of atoms and bonds, there will be the same amount of atoms at the beginning of an experiment as the amount of atoms at the end of experiment. All that will have happened, is that during the reaction, bonds will have been broken and formed making new compounds. However, the amount of atoms remains exactly the same because matter can not be created or destroyed
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Answer:
2.74 percent hydrogen and 97.3 percent chlorine are in 2 g of compound.
The same as initial
Explanation:
HCl → H⁺ + Cl⁻
2.74% H means that in 100 g of compund, 2.74 grams are H
97.3 % Cl means that in 100 g of compound, 97.3 grams are Cl
So how many grams of H and Cl, are in 1 g of compound
100 g ___ 2.74 g are H _____ 97.3 g are Cl
1g _____ 2.74/100 ____ 97.3/100
0.0274 g are H
0.973 g are Cl
In 2 grams we will find
0.0274 g .2 = 0.0548 g of H
0.973 g .2 = 1.946 g of Cl
(grams / total grams) . 100 = %
(0.0548/2 ) .100 = 2.74%
(1.946 /2) .100 = 97.3%
