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oee [108]
3 years ago
8

The product of a combination reaction is Ba(OH)2 . If one of the reactants is H2O , what is the other reactant

Chemistry
2 answers:
Gnoma [55]3 years ago
7 0

BaO..........................

exis [7]3 years ago
3 0

The other reactant in the given reaction is \boxed{{\text{BaO}}}.

Further explanation:

A chemical reaction involves the rearrangement of the constituents of reactants to form new substances called products. Chemical reactions can be classified into the following five types:

1. Combination reactions

The chemical reactions where the combination of two or more reactants yields a single product are known as combination reactions. These are normally exothermic in nature.

Examples of combination reactions are as follows:

(a) {{\text{H}}_2} + {\text{C}}{{\text{l}}_2} \to {\text{2HCl}}  

(b) {\text{CaO}} + {{\text{H}}_2}{\text{O}} \to {\text{Ca}}{\left( {{\text{OH}}} \right)_2}  

2. Decomposition reactions

In these types of reactions, two or more products are produced from a single reactant. These are usually endothermic in nature.

Examples of decomposition reactions are as follows:

(a) 2{{\text{H}}_2}{{\text{O}}_2} \to 2{{\text{H}}_2}{\text{O}} + {{\text{O}}_2}  

(b) 2{\text{NaCl}} \to {\text{2Na + C}}{{\text{l}}_2}  

3. Displacement reactions

In these reactions, one of the reactants replaces another one due to its high reactivity. These reactions are also called replacement reactions.

Examples of displacement reactions are as follows:

(a) {\text{Cu}} + {\text{AgN}}{{\text{O}}_3} \to {\text{Ag}} + {\text{Cu}}{\left( {{\text{N}}{{\text{O}}_3}} \right)_2}  

(b) {\text{C}}{{\text{l}}_2} + {\text{KBr}} \to {\text{B}}{{\text{r}}_2} + {\text{KCl}}  

4. Double displacement reactions

In these reactions, ions of two compounds interchange with each other to form the product.

Examples of double displacement reactions are as follows:

(a) {\text{N}}{{\text{a}}_2}{\text{S}} + {\text{HCl}} \to {\text{NaCl}} + {{\text{H}}_2}{\text{S}}  

(b) 2{\text{KOH}} + {\text{Cu}}{\left( {{\text{N}}{{\text{O}}_{\text{3}}}} \right)_2} \to 2{\text{KN}}{{\text{O}}_3} + {\text{Cu}}{\left( {{\text{OH}}} \right)_2}  

5. Combustion reactions

These reactions occur when hydrocarbons are burnt in the presence of oxygen. Here, carbon dioxide and water are produced.

Example of combustion reactions are as follows:

(a) {\text{C}}{{\text{H}}_4} + {{\text{O}}_2} \to {\text{C}}{{\text{O}}_2} + {{\text{H}}_2}{\text{O}}  

(b) {{\text{C}}_{10}}{{\text{H}}_{14}} + 12{{\text{O}}_2} \to 10{\text{C}}{{\text{O}}_2} + 4{{\text{H}}_2}{\text{O}}  

One of the reactants is {{\text{H}}_{\text{2}}}{\text{O}} and the given reaction is a combination reaction. When BaO reacts with {{\text{H}}_{\text{2}}}{\text{O}}, it produces {\text{Ba}}{\left( {{\text{OH}}} \right)_{\text{2}}}. The reaction occurs as follows:

 {\text{BaO}} + {{\text{H}}_{\text{2}}}{\text{O}} \to {\text{Ba}}{\left( {{\text{OH}}} \right)_{\text{2}}}

Therefore the other reactant in the given reaction is found to be BaO.

Learn more:

  1. Balanced chemical equation: brainly.com/question/1405182
  2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: High School

Chapter: Chemical reaction and equation

Subject: Chemistry

Keywords: types of reactions, combination reaction, decomposition reaction, double displacement reaction, combustion reaction, BaO, H2O, Ba(OH)2, reactants, products.

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4. When 1.00 L of 1.00 M Ba(NO3)2 solution at 25.0˚C is mixed with 1.00 L of 1.00 M Na2SO4 solution at 25.0˚C in a calorimeter,
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Answer:

The final temperature of the mixture is 28.11 °C

Explanation:

Step 1: Data given

Volume of 1.00 M Ba(NO3)2 = 1.00 L

Temperature = 25.0 °C

Volume of 1.00 M Na2SO4 = 1.00 L

enthalpy change is – 26 kJ per mol BaSO4

The specific heat of water is 4.18 J/g ·˚C

the density of water is 1.00 g/mL

Step 2: The balanced equation

Ba(NO3)2(aq) + Na2SO4(aq) → 2NaNO3(aq) + BaSO4(s)

Step 3: Calculate the total volume

Total volume = 1.00 L + 1.00 L = 2.00 L = 2000 mL

Step 4: Calculate mass

Mass = volume * density

Mass = 2000 mL * 1g/mL

Mass = 2000 grams

Step 5: Calculate moles BaSO4 formed

For 1 mol Ba(NO3)2 we need 1 mol Na2SO4 to produce 1 mol BaSO4

There is no limiting reactant, both Ba(NO3)2 and Na2SO4 will be completely be consumed (1 mol). We'll have 1.0 mol of BaSO4 produced.

Step 6: Calculate Q

Q = - ΔH

ΔH is negative so the reaction is exothermic, what means the temperature increases

Q is always positive, so Q = 26kJ = 26000 J

Step 6: Calculate the heat transfer

Q= m*c*ΔT

⇒with Q = the heat transfer = TO BE DETERMINED

⇒with m =the mass of the solution = 2000 grams

⇒with c= the specific heat of the solution = 4.18 J/g°C

⇒with ΔT = the change of temperature = T2 - T1 = T2 - 25.0

26000 = 2000 * 4.18 * (T2 - 25.0 °C)

3.11 = T2 - 25.0 °C

T2 = 25.0 + 3.11 °C

T2 = 28.11 °C

The final temperature of the mixture is 28.11 °C

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3 years ago
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