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gizmo_the_mogwai [7]
3 years ago
7

_____ Ca(NO3)2 + _____ Fe → _____ Fe(NO3)3 + _____ Ca I need this done quick and fast Balancing chemical equations

Chemistry
1 answer:
cupoosta [38]3 years ago
8 0

Answer:

3, 2, 2,3

..........................

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The ka of hf is 6.8 x 10-4. what is the ph of a 0.35 m solution of hf?
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When the reaction equation is:

HF ↔ H+   +   F-

and when the Ka expression
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so, Ka = [H+][F-]/[HF]

when we assume:

[H+] = [F-] = X

and [HF] = 0.35 - X

So, by substitution:

6.8 x 10^-4 = X^2 / (0.35 - X) by solving for X

∴ X = 0.015 M

∴[H+] = X = 0.015

when PH = -㏒[H+]

∴PH = -㏒0.015

        = 1.8
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3 years ago
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