Answer:
w = 0.626 rad / s, v = 3.13 m/s
Explanation:
For this exercise let's use Newton's second law
F = m a
Where the force is a friction force and the acceleration is centripetal,
a = v² / r = w² r
The formula for friction force
fr = μ N
In a free body diagram
N- W = 0
W = N
The frictiμon outside goes from zero to the maximum value, let's calculate the speed for the maximum value of the friction force, replace
μ m g = m w² r
w = √ μ g / r
Let's calculate
w = √(0.2 9.8 / 5)
w = 0.626 rad / s
angular and linear velocity are related
v = w r
v = 0.626 5
v = 3.13 m/s
Answer: Combustion of Hydrocarbons
Explanation:
The Independent variable in an experiment is the one whose effect on the dependent variable is being measured. The independent variable therefore is controlled to see the effect it will have in the experiment.
In this experiment, the scientists combusted different types of hydrocarbons (diesel, gasoline, natural gas and a gasoline/ethanol mixture) as they aimed to find out the effect that this burning would have on the environment thereby making the combustion of hydrocarbons the independent variable.
Answer:
Increased, 5%
Explanation:
Recent studies conducted on online dating sites established that the response of female users increased by 5% when emotions are in their profiles even as for male users' response also increased by 8%. Another study also revealed that those who have never used online dating sites and/or mobile dating apps believe that people who use dating apps are desperate.
Answer:
Machinist
Explanation:
A skilled worker with the ability to operate computer numerically controlled (CNC) machines is qualified to work in a machinist position.
A machinist is a person who is properly skilled and consists of advanced knowledge regarding the functions of a CNC machine. He can use different mechanisms and complex numerical functions of the machine to carry out different tasks. Any person who lacks the official learning of mechanisms cannot operate such machines effectively.
Answer:
57.8408 kPa
Explanation:
Data provided in the question:
Density of oxygen contained, ρ = 2.0 kg/m³
Temperature, T = 25 °C = 25 +273 = 298 K
Atmospheric pressure = 97 kPa.
Now,
Pressure due to gas = ρRT
Here,
R is the gas constant = 259.8 J/kg.K
Thus,
Absolute Pressure due to oxygen = 2 × 259.8 × 298
= 154840.8 Pa
= 154840.8 × 10⁻³ kPa
= 154.84 kPa
Thus,
Gage pressure = Absolute Pressure - Atmospheric pressure
= 154.84 kPa - 97 kPa
= 57.8408 kPa