Question

What is the torque τa about axis a due to the force f⃗ ? express the torque about axis a at cartesian coordinates (0,0)?

Answer 1

Answer:

$\tau_a = F a sin \theta$

Explanation:

The torque of a force is given by:

$\tau = F d sin \theta$

where

F is the magnitude of the force

d is the distance between the point of application of the force and the centre of rotation of the system

$\theta$ is the angle between the direction of the force and d

In this problem, we have:

$F$, the force

$a$, the distance of application of the force from the centre (0,0)

$\theta$, the angle between the direction of the force and a

Therefore, the torque is

$\tau_a = F a sin \theta$