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Reptile [31]
3 years ago
7

How have moral and ethical issues influenced science

Physics
1 answer:
umka2103 [35]3 years ago
6 0
Often times, moral and ethical issues could hindrance the development of science.
For example, the cloning technology has been hindranced by these type of issues since the beginning of its creation.
The moral and ethical aspect of society somehow oppose the technology because they feel that the sicentists are 'playing God' and doing something that humans are not suppose to be doing, even though there might be overwhelming benefits from the technology.
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A 225 kg block is pulled by two horizontal forces. The first force is 178 N at a 41.7-degree angle and the second is 259 N at a
yawa3891 [41]

Answer:

52.9 N, 364.7 N

Explanation:

First of all, we need to resolve both forces along the x- and y- direction. We have:

- Force A (178 N)

A_x = (178 N)(cos 41.7^{\circ})=132.9 N\\A_y = (178 N)(sin 41.7^{\circ})=118.4 N

- Force B (259 N)

B_x = (259 N)(cos 108^{\circ})=-80.0 N\\B_y = (259 N)(sin 108^{\circ})=246.3 N

So the x- and y- component of the total force acting on the block are:

R_x = A_x + B_x = 132.9 N - 80.0 N =52.9 N\\R_y = A_y + B_y = 118.4 N +246.3 N = 364.7 N

7 0
3 years ago
A. Which of the four thermal processes describes the pressure-volume relationship at a constant temperature?
zhannawk [14.2K]
Boyles law describes pressure volume relationship at constant temperature  pressure is directly proportional  to volume at constant tamparature
4 0
3 years ago
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Which of the following will cause a decrease in an object's weight? Increase in the mass of the object Decrease in the mass of t
Paul [167]
A decrease in mass will decrease an objects weight because 
weight = mass x gravitational constant
4 0
3 years ago
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What is the work energy transfer equation?
rosijanka [135]

Answer:

The equation used to calculate the work done is: work done = force × distance. W = F × d. This is when: work done (W) is measured in joules (J)

8 0
3 years ago
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A solid, horizontal cylinder of mass 18.0 kg and radius 1.70.0 m rotates with an angular speed of 40 rad/s about a fixed vertica
Radda [10]

Answer:39.88 rad/s

Explanation:

Given

mass of cylinder m_1=18 kg

radius R=1.7 m

angular speed \omega =40rad/s

mass of m_2=0.8 kg dropped at r=0.3 m from center

let \omega _2 be the final angular velocity of cylinder

Conserving Angular momentum

L_1=L_2

\left ( \frac{m_1R^2}{2}\right )\omega =\left ( \frac{m_1R^2}{2}+m_2r^2\right )\omega _2

\left ( \frac{18\cdot 1.7^2}{2}\right )\cdot 40=\left ( \frac{18\cdot 1.7^2}{2}+0.8\cdot 0.3^2\right )\omega _2

26.01\times 40=26.082\times \omega _2

\omega _2=39.88 rad/s

3 0
3 years ago
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