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IrinaVladis [17]
3 years ago
6

Which of the following can you physically change for a pure substance such as water, without altering the chemical composition?

Chemistry
1 answer:
ZanzabumX [31]3 years ago
4 0
Color most likely.

Step by step explanation:
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How many half-lives will pass by the time 1.56% of I-131 is present? B. Approximately how many days does that equal? *
serg [7]

Answer: Hmmmmm that's crazy....

There are a couple of equations one could use for this type of problem, but I find the following to be the easiest to use and to understand.

Fraction remaining (FR) = 0.5n

n = number of half lives that have elapsed

In this problem, we need to find n and are given the FR, which is 1.56% or 0.0156 (as a fraction).

0.0156 = 0.5n

log 0.0156 = n log 0.5

-1.81 = -0.301 n

n = 6.0 half lives have elapsed

Explanation:

Just wanted to help. Hopefully it's correct wouldn't want to waster your time ;)

6 0
3 years ago
In a chemical equation, the symbol that means "dissolved in water" is _____. (s) (l) (aq) (g)
Paraphin [41]
In a chemical equation, the symbol that means “dissolved in water” is (aq).
8 0
3 years ago
You know that chemical a reacts with chemical
Jet001 [13]
The chemical reaction would most likely be written as follows:
A + B = AB
We cannot simply use the usual method of converting grams to moles since we do not have any idea on what are the identities of A and B. The only method we could use is to use the law of conservation of mass where mass inflow in a process should be equal to the mass out in the process. The total inflow of mass would be the mass of A and B and the outflow would be the product AB.  

mass of A + mass of B = mass of AB
10.0 g A + 10.0 g B = mass of AB
mass of AB = 20.0 g 
7 0
4 years ago
Calculate the fraction of lattice sites that are schottky defects for cesium chloride at its melting temperature (645oc). assume
baherus [9]
Answer : 7.87 X 10^{-6}.

Explanation : To find the fraction of schottky defects in the given lattice of CsCl,

we use the formula, \frac{N_{s} }{N}} = exp ( \frac{-Q_{s}}{2KT} )

on solving with the given values ,Q_{s}= 1.86 eV and T as 645 + 273 K and rest are the constants.

\frac{N_{s} }{N}} = exp ( \frac{-1.86 eV}{2 X (8.62 X 10^{-5}) X (645 +273)} )

we get the answer as 7.87 X 10^{-6}.
6 0
3 years ago
Read 2 more answers
Explain how/why you categorized the substances the way you did. What characteristics of the substances helped you predict whethe
Rasek [7]

The presence of hydrogen and hydroxyl ions determines the acidic and basic nature of a solution.

<h3>What determine acidic and basic nature of a solution?</h3>

The use of the pH scale is one way of determining the acidic and basic nature of solution. If the pH of a solution is less than 7, it is considered as acidic and if the pH is 7, the solution is neutral.

While if the pH is greater than 7,the solution is basic so we can conclude that the presence of hydrogen and hydroxyl ions determines the acidic and basic nature of a solution.

Learn more about substance here: brainly.com/question/2901507

6 0
2 years ago
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