Answer:
Fe2O3, Fe2S3 and FeCl3
Explanation:
The formular shows the number of atoms of element present in the compound. The number of atoms in turn depends on the charges. The goal is to have a neutral compound with oxidation number of zero.
Oxide:
Iron(Fe) has oxidation number (O.N) of +3, oxygen has O.N of -2. The formular with a balanced (Charge = 0) O.N number is; Fe2O3
Sulphide:
Iron(Fe) has oxidation number (O.N) of +3, sulphur has O.N of -2. The formular with a balanced (Charge = 0) O.N number is; Fe2S3
Chloride:
Iron(Fe) has oxidation number (O.N) of +3, chlorine has O.N of -1. The formular with a balanced (Charge = 0) O.N number is; FeCl3
Answer : The conditional formation constant is
Explanation :
First we have to calculate the formation constant.
As we are given that:
Thus, the formation constant is
Now we have to calculate the conditional formation constant.
The expression used as:
where,
= conditional formation constant = ?
= activity coefficient at pH 9.00 = 0.041
= formation constant =
Now put all the given values in the above expression, we get:
Therefore, the conditional formation constant is
I believe the answer is 4 carbons. Glycolysis involves break down of glucose to two molecules of pyruvic acid (3 carbons) under aerobic conditions. At the end of glycolysis the two pyruvate molecules undergoes pyruvate oxidation to capture the remaining energy in the form of ATP. A carboxyl group is removed from pyruvate and released in the form carbon dioxide, leaving a two carbon molecule which forms Acetyl-CoA (2 molecules). Acetyl-CoA then serves as a fuel for the citric acid cycle in the next stage of cellular respiration.
Answer:What is your question?
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