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kakasveta [241]
3 years ago
5

Homogeneous mixtures can exist

Physics
1 answer:
irga5000 [103]3 years ago
7 0

Answer:

.................True?

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Help pls .. Which image shows an example of the strong nuclear force in action?
Vedmedyk [2.9K]

Answer:

The answer is D.

Explanation:

Just took the quiz. Not sure if u still need help

3 0
3 years ago
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What is the reactance of a capacitor at a 8.0 μF frequency of 56.0 Hz?
il63 [147K]

Answer:

35.55 ohm

Explanation:

C = 80 micro farad

F = 56 hertz

Reactance

Xc = 1 / (2 × pi × F × C)

Xc = 1 / ( 2 × 3.14 × 56 × 80 × 10^-6)

Xc = 35.55 ohm

8 0
4 years ago
You're driving down the highway late one night at 22 m/s when a deer steps onto the road 38 m in front of you. Your reaction tim
sleet_krkn [62]

speed of the car is given on the road

v = 22 m/s

reaction time is given as

t = 0.50 s

now we can find the distance that it will move during this reaction time

d_1 = 22* 0.50 = 11 m

now the deceleration of the car is 10 m/s^2

so the distance that it will move before stop is given by

v_f^2 - v_i^2 = 2 a d

0^2 - 22^2 = 2*(-10)*d

d = 24.2 m

so the total distance that it require to stop is given as

d = 24.2 + 11 = 35.2 m

while the deer is standing at distance 38 m

so the car will stop 2.8 m before the position of deer


3 0
3 years ago
What is the strength of an electric field that will put a force of<br> 1.28 x 10-15 N on a proton?
PilotLPTM [1.2K]

Answer: E =  7,490.6 N/C

Explanation:

If we have a field E, and a particle with a charge q, the force that the particle experiences is:

F = E*q

In this case, we know that the force is:

F = 1.2*10^(-15) N

And we know that the particle is a proton, where the charge of a proton is:

q = 1.602*10^(-19) C

Then we can replace these two values in the equation to get:

1.2*10^(-15) N = E*1.602*10^(-19) C

We just need to isolate E.

(1.2*10^(-15) N)/(1.602*10^(-19) C) = E

7,490.6 N/C = E

That is the strength of the electric field.

8 0
3 years ago
What do you mean by the statement relative density of gold is 19.3
sergey [27]
The relative density of gold is 19.3 it means the ratio obtained by dividing the density of gold by water at temp of 4 degree celcius is 19.3
8 0
3 years ago
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