Answer: It will take 11.775 seconds.
Explanation: As a sphere with a diameter of 0.1 mm, the area of an alveolus is
A = 4.π.r²
r for an alveolus would be: r = 0.00005m or r = 5.
m
Finding the area:
A = 4.3.14.(5.)²
A = 3.14.
m²
The concentration change is to be 90% of the final, so
c = 0.9.3.14.
c = 28.26.
The oxygen diffusivity is 2.4.m²/s, that means in 1 second 2.4. of oxygen spread in one alveolus area. So:
1 second = 2.4.m²
t seconds = 28.26.m²
t = 
t = 11.775s
For a concentration change at the center to be 90%, it will take 11.775s.
Based on Le Chatelier's principle, the following factors will affect the chemical equilibrium
1) Temperature
2) Pressure
3) concentration
4) catalyst
The given equilibrium involves
H2(g) + I2(g) → 2HI(g)
The reactants are H2 and I2 while the product is HI. The equilibrium will be affected by changes in the concentration of H2, I2 or HI.
However, the equilibrium will not be affected by the addition of N2 since it is not involved in the reaction
Ans (c)
Answer:
The water lost is 36% of the total mass of the hydrate
Explanation:
<u>Step 1:</u> Data given
Molar mass of CuSO4*5H2O = 250 g/mol
Molar mass of CuSO4 = 160 g/mol
<u>Step 2:</u> Calculate mass of water lost
Mass of water lost = 250 - 160 = 90 grams
<u>Step 3:</u> Calculate % water
% water = (mass water / total mass of hydrate)*100 %
% water = (90 grams / 250 grams )*100% = 36 %
We can control this by the following equation
The hydrate has 5 moles of H2O
5*18. = 90 grams
(90/250)*100% = 36%
(160/250)*100% = 64 %
The water lost is 36% of the total mass of the hydrate
