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dem82 [27]
4 years ago
12

Before an object can react to a force the object must contain what?

Physics
1 answer:
Serggg [28]4 years ago
6 0

Energy I believe. If there is no energy given or taken the object will not react.

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What is the velocity of a jet that travels 785 m [W] in 2.39 s?
Cerrena [4.2K]

Answer:

v = 328.4

Explanation:

Data:

  • Distance (d) = 785 m
  • Time (t) = 2.39 s
  • Velocity (v) = ?

Use formula:

  • \boxed{v = \frac{d}{t}}

Replace:

  • \boxed{v = \frac{785m}{2.39s}}

It divides:

  • \boxed{v = 328.4\frac{m}{s}}}

What is the velocity?

The velocity is <u>328.4 meters per second.</u>

7 0
3 years ago
Assuming the starting height is 0.0 m, calculate the potential energy of the cart after it has been elevated to a height of 0.5
Bogdan [553]
The potential energy is most often referred to as the "energy at rest" and is dependent on the elevation of an object. This can be calculated through the equation,

     E = mgh

where E is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. In this item, we are not given with the mass of the cart so we assume it to be m. The force is therefore,

   E = m(9.8 m/s²)(0.5 m) = 4.9m

Hence, the potential energy is equal to 4.9m.
8 0
4 years ago
A cylinder of radius r=10.0 cm and height h=20.0 cm
Olenka [21]
D I think is the correct answer
If the cylinder is slightly
7 0
2 years ago
A wheel rotates without friction about a stationary horizontal axis at the center of the wheel. A constant tangential force equa
ivann1987 [24]

Answer:

The moment of inertia of the wheel is 0.593 kg-m².

Explanation:

Given that,

Force = 82.0 N

Radius r = 0.150 m

Angular speed = 12.8 rev/s

Time = 3.88 s

We need to calculate the torque

Using formula of torque

\tau=F\times r

\tau=82.0\times0.150

\tau=12.3\ N-m

Now, The angular acceleration

\dfrac{d\omega}{dt}=\dfrac{12.8\times2\pi}{3.88}

\dfrac{d\omega}{dt}=20.73\ rad/s^2

We need to calculate the moment of inertia

Using relation between torque and moment of inertia

\tau=I\times\dfrac{d\omega}{dt}

I=\dfrac{I}{\dfrac{d\omega}{dt}}

I=\dfrac{12.3}{20.73}

I= 0.593\ kg-m^2

Hence, The moment of inertia of the wheel is 0.593 kg-m².

5 0
3 years ago
bonnie pulls a cart that weighs 195 N with a force of 18.0 N. According to Newton's 3rd law, with what force does the cart pull
motikmotik

Answer:

The force exerted by the cart on Bonnie is - 18.0 N

Explanation:

Given;

weight of the cart, w = 195 N

Bonnie's applied force on the cart, F = 18.0 N

According to Newton's 3rd law, action and reaction are equal and opposite.

Thus, the cart will pull back at Bonnie with force of equal magnitude but in opposite direction.

The force exerted by the cart on Bonnie = - 18.0 N

4 0
3 years ago
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