Before an object can react to a force the object must contain what?

Physics

1 answer:

Serggg [28]4 years ago

6 0

Energy I believe. If there is no energy given or taken the object will not react.

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Meeta used an elastic tape to measure the length of her window to stitch a curtain. Do you think she will be able to stitch a cu

Yuki888 [10]

Answer:

Explanation:

She will not be able to measure the length of her window accurately due to instrumental error from her choice of instrument. The elastic nature of her tape would alter the measurement because it will stretch as she is taking her readings, thus reducing the true measurement of the length of her window.

To measure the length of her window, she could use an inelastic tape rule or a metre rule. These instruments would eliminate instrumental error.

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3 years ago

A car travels along a highway with a velocity of 24 m/s, west. The car exits the highway; and 4.0 s later, its instantaneous vel

zloy xaker [14]

Answer:

$4.25 m/s^{2}$

Explanation:

Change in velocity considering the x component will be

Final velocity-Initial velocity

$\triangle v_x= 16cos 45^{\circ}-24=-12.6862915 m/s$

Change in velocity considering the y component will be

Final velocity-Initial velocity

$\triangle v_y= 16sin 45^{\circ}-0=11.3137085 m/s$

Resultant change in velocity $=\sqrt {(-12.6862915 m/s)^{2}+(11.3137085 m/s)^{2}}=16.9982938 m/s$

Acceleration= change in velocity per unit time hence

$a= \frac {16.9982938}{4}=4.24957345\approx 4.25 m/s^{2}$

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3 years ago

It is essential to behave appropriately on social media and be _______ when you post anything.

Firdavs [7]

Answer:

I would say be Mindful.

Explanation:

There could be like a MILLION answers for this. I think that you should personally go with your gut. That would be the best option. I think it's mindful because you really do have to be mindful when you post. Like not posting too much, not posting stuff you're uncomfortable with, not posting when on vacation, etc. So, I think you should be mindful.

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2 years ago

If two equal charges are separated by a certain distance, the force of repulsion is F. Given F1, if each charge in F1 is doubled

Alisiya [41]

Answer: $F_2=16\times F_1$