Answer:
48g of Magnesium.
Explanation:
We know that:
Mole=given mass/molar mass
Then, moles of aluminum = 54/27 = 2.
A/c to question ,
For 2 moles of magnesium it's mass is 2×24=48g.
Hence, the required mass for same number of magnesium atoms is 48g.
(Hope this helps can I pls have brainlist (crown)☺️)
Be, Mg, Ca increasing first ionization energy
Density = mass/ volume
mass= 9.6 g
Volume of the object = 13.2-10.0 =3.2 ml=3.2 cm³
1ml =1 cm³
D=9.6g/3.2 cm³ = 3.0 g/cm³
I think it's 2 I tried looking it up because I was not sure.
After first half-life you will have 100/2=50g. After second half-life you will have 50/2=25g.