How much heat is absorbed when 30.00 g of C(s) reacts in the presence of excess SO2(g) to produce CS2(l) and CO(g) according to
the following chemical equation?
5 C(s) + 2 SO2(g) → CS2(l) + 4 CO(g) ΔH° = +239.9 kJ
1 answer:
Answer:
120.0 kJ
Explanation:
- First we convert the given mass of C to moles:
30.00 g C ÷ 12g/mol = 2.5 mol
- The ΔH° value given by the problem, is the heat absorbed when 5 moles of C react.
So when we have<u> half the moles of C</u> (2.5 instead of 5.0), t<u>he heat absorbed will also be half</u>, thus the answer is:
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