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timurjin [86]
3 years ago
6

How many moles of nitrogen are in 3.7 moles of C8H11NO2?

Chemistry
1 answer:
Phoenix [80]3 years ago
4 0
<h3>Answer:</h3>

               3.7 Moles of Nitrogen

<h3>Explanation:</h3>

                      On observing the chemical formula C₈H₁₁NO₂ (might be formula of Dopamine) it is found that one mole of this compound contains;

8 Moles of Carbon

11 Moles of hydrogen

1 Mole of Nitrogen and

2 Moles of Oxygen respectively.

<u>Calculate Number of Moles of Nitrogen:</u>

As,

                   1 Mole of C₈H₁₁NO₂ contains  =  1 Mole of Nitrogen

So,

            3.7 Moles of C₈H₁₁NO₂ will contain  =  X Moles of Nitrogen

Solving for X,

                       X  =  (3.7 Moles × 1 Mole) ÷ 1 Mole

                       X  =  3.7 Moles of Nitrogen

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When The rate of effusion is inversely proportional to the √molar mass of the substance.
and we have R(He) = 1L / 4.5 min so,
R(He)/R(Cl2) = (molar mass of Cl2/ molar mass of He)^0.5
and when we have the molar mass of Cl2 = 70.9  & the molar mass of He = 4
so by substitution:
(1L/4.5 min)/ R(Cl2) = (70.9 / 4)^0.5
(1L/4.5 min) / R(Cl2) = 4.21
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