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stich3 [128]
3 years ago
9

If an object is moving with constant velocity, what do you know about its acceleration?

Physics
1 answer:
Ivan3 years ago
8 0
It's equals to zero (a=0)
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What is the mean height for the grass used as a control?
motikmotik
The mean height for the grass used as a control is equal to the total number of the data came from the control grass divided by the number of control grass in the experiment. The mean height means the average height of the grass.
5 0
3 years ago
A 4,350 kg truck traveling east has a momentum of 26,100kg m/s what's the trucks velocity
Angelina_Jolie [31]

Answer:

6 m/s East

Explanation:

Momentum = Mass . Velocity

26100 = 4350. Velocity

Velocity = 6m/s East

4 0
3 years ago
Clouds are formed when water vapor in the atmosphere becomes a liquid and condenses. Condensation is a result of the difference
aleksklad [387]

Answer:

B temperature and dew point temperature

4 0
2 years ago
A metal detector used in airports is actually a large coil of wire carrying a small current. Explain how it detects a gun, even
Alexus [3.1K]

<u>Metal detectors work by transmitting an electromagnetic field from the search coil into the ground. Any metal objects (targets) within the electromagnetic field will become energised and retransmit an electromagnetic field of their own. The detector’s search coil receives the retransmitted field and alerts the user by producing a target response. metal detectors are capable of discriminating between different target types and can be set to ignore unwanted targets. </u>

1. Search Coil

The detector’s search coil transmits the electromagnetic field into the ground and receives the return electromagnetic field from a target.

2. Transmit Electromagnetic Field (visual representation only - blue)

The transmit electromagnetic field energises targets to enable them to be detected.

3. Target

A target is any metal object that can be detected by a metal detector. In this example, the detected target is treasure, which is a good (accepted) target.

<em>hope this helps PLEASE MARK AS BRAINLIEST:)</em>

8 0
3 years ago
A charge −1.3 × 10−5 C is fixed on the x-axis at 7 m, and a charge 1 × 10−5 C is fixed on the y-axis at 4 m. Calculate the magni
wariber [46]

Answer:

6104 N/C.

Explanation:

Given:

k = 8.99 × 10^9 Nm2/C^2

Qx = 1.3 × 10^-5 C

rx = 7 m

Qy = 1 × 10−5 C

ry = 4 m

E = F/Q

= kQ/r^2

Ex = (8.99 × 10^9 × 1.3 × 10^−5) ÷ 7^2

= 2385.1 N/C.

Ey = (8.99 × 10^9 × 1.0 × 10^−5) ÷ 4^2

= 5618.75 N/C

Eo = sqrt(Ex^2 + Ey^2)

= sqrt(3.157 × 10^7 + 5.69 × 10^6)

= 6104 N/C.

5 0
3 years ago
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