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miskamm [114]
3 years ago
5

4. In a solution of sugar water, sugar is the ______. (SPS6a; DOK2)

Chemistry
2 answers:
Rzqust [24]3 years ago
6 0

Answer:

B. solute

Explanation:

lana [24]3 years ago
4 0

4. In a solution of sugar water, sugar is the ______. (SPS6a; DOK2)

<u>a. solvent</u>

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A disk of radius 2.0 cm has a surface charge density of 6.3 μC/m2 on its upper face. What is the magnitude of the electric field
maksim [4K]

Answer:

the electric field at Z = 12 cm is E =   9.68 × 10³ N/C = 9.68 kN/C

Explanation:

Given: radius of disk, R = 2.0 cm = 2 × 10⁻² cm, surface charge density,σ = 6.3 μC/m² = 6.3 × 10⁻⁶ C/m², distance on central axis, z = 12 cm = 12 × 10⁻² cm.

The electric field, E at a point on the central axis of a charged disk is given by E = σ/ε₀(1 - \frac{z}{\sqrt{z^{2} + R^{2} }  })

Substituting the values into the equation, it becomes

E = σ/ε₀(1 - \frac{z}{\sqrt{z^{2} + R^{2} }  }) = 6.3 × 10⁻⁶/8.854 × 10⁻¹²(1 - \frac{0.12}{\sqrt{0.12^{2} + 0.02^{2} } }) = 7.12 × 10⁵(1 - \frac{0.12}{0.1216}) = 7.12 × 10⁵(1 - 0.9864) = 7.12 × 10⁵ × 0.0136 = 0.0968 × 10⁵ = 9.68 × 10³ N/C = 9.68 kN/C

Therefore, the electric field at Z = 12 cm is E =   9.68 × 10³ N/C = 9.68 kN/C

7 0
3 years ago
Sulphuric acid is a strong acid but acetic acid is weak acid why​
Lemur [1.5K]

Answer:

sulphuric is a strong acid

Explanation:

Sulphuric is a strong acid because it completely ionises in water while acetic acid partially ionises in water

8 0
3 years ago
Alcohols are polar molecules. true false
viktelen [127]
All alcohols are polar. True
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2 years ago
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leva [86]

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4 0
2 years ago
Lab 27. stoichiometry and chemical reactions: which balanced chemical equation best represents the thermal decomposition of sodi
Cloud [144]
Answer:
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<span>                       2 NaHCO</span>₂<span> </span> →<span>  Na</span>₂<span>CO</span>₃<span> (s)  </span>+ <span> CO</span>₂<span> (g)  +  H</span>₂<span>O (g)
</span>
Explanation:
                   Let suppose you burn 168 g ( 2 moles ) of NaHCO₃, a gas will produced and product is left behind. On measuring the product formed it will be almost equal to 105 g. This shows that the product is Na₂CO₃ and 1 mole of it is being produced after decomposition of sodium bicarbonate.
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2 years ago
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