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nasty-shy [4]
3 years ago
6

How many significant figures will be in the final answer of this calculation? 20.2 + 3.10 - 0.09687 = ________

Chemistry
1 answer:
Lana71 [14]3 years ago
4 0
There will be seven characters so the answer is e
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F 2.50 × 10−2 g of solid Fe(NO3)3 is added to 100. ML of a 1.0 × 10−4 M NaOH solution, will a precipitate form? (ksp=4 × 10−38 f
vladimir1956 [14]

Answer:

A precipitate will be formed

Explanation:

The Ksp equilibrium of Fe(OH)₃ is:

Fe(OH)₃ (s) ⇄ Fe³⁺(aq)+ 3OH⁻(aq)

And its expression is:

Ksp = 4x10⁻³⁸ = [Fe³⁺] [OH⁻]³

<em>Where the concentrations are concentrations in molarity in equilibrium,</em>

We can write Q as:

Q = [Fe³⁺] [OH⁻]³

<em>Where [] are actual concentrations in molarity of each specie.</em>

<em />

When Q>= Ksp; a precipitate is formed,

When Q< Ksp no precipitate is produced:

[OH⁻] = [NaOH] = 1.0x10⁻⁴M

[Fe²⁺] = 2.50x10⁻²g * (1mol / 179.85g) / 0.100L = 1.39x10⁻³M

<em>179.85g/mol is molar mass of Fe(NO₃)₂ and the volume of the solution is 0.100L = 100mL</em>

<em />

Q = [Fe³⁺] [OH⁻]³

Q = [ 1.39x10⁻³] [ 1.0x10⁻⁴]³

Q = 3.8x10⁻¹⁵

As Q >> Ksp; A precipitate will be formed

7 0
3 years ago
250 ml of seawater and we inked each molecule with pink color, then we mixed this 250 ml in the ocean. After mixing you took 250
Marysya12 [62]

Answer:

9.77 × 10⁹ molecules

Explanation:

Since the density of water is 1 g/cm³ = 1000 g/L

So, we find the mass of sea water in 250 mL = 0.250 L

We know density = mass/volume

mass = density × volume = 1000 g/L × 0.250 L = 250 g

Now we calculate the number of moles of sea water in 250 g, 250 mL of sea water.

number of moles n = mass of sea water,m/molar mass of water, M

molar mass of water, M = 18 g/moL

n = m/M = 250 g/18 g/mol = 13.89 mol

We now calculate the number of molecules present in the 250 mL of sea water.

n = N/N' where N = number of molecules, N' = avogadro's number = 6.022 × 10²³/mol

So,N =nN' = 13.89 mol × 6.022 × 10²³/mol = 8.36 × 10²⁴ molecules

Now, the volume of the ocean is 1.337 × 10¹⁸ m³ = 1.337 × 10¹⁵ L

Since the 250 mL sea water is mixed with the ocean, the number of molecules per liter is 8.36 × 10²⁴ molecules/1.337 × 10¹⁵ L = 6.25 × 10⁹ molecules/L

If we now take 250 mL out of the ocean, the number of molecules in this 250 mL will be 6.25 × 10⁹ molecules/L × 250 mL =  6.25 × 10⁹ molecules/L × 0.250 L = 9.77 × 10⁹ molecules.

So, we have 9.77 × 10⁹ molecules of pink molecules in the 250 mL after mixing in the ocean.

6 0
3 years ago
What mass of oxygen is needed to burn 54.0 grams of butane c4h10
Jobisdone [24]

The moles of oxygen required to burn Butane is 6 moles.

<h3>What is a Combustion Reaction?</h3>

A reaction in which fuel gets oxidised by an oxidising agent producing a large amount of heat is called a combustion reaction.

In this question

Butane is burnt with oxygen

Molar mass of C₄H₁₀ = (12.0×4 + 1.0×10) g/mol = 58.0 g/mol

Molar mass of O₂ = 16.0×2 g/mol = 32.0 g/mol

Balanced equation for the reaction:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Mole ratio C₄H₁₀ : O₂ = 2 : 13

The given mass = 54grams

moles = 54/58 = 0.93 moles

The mole of oxygen required =

0.93/ x = 2/13

0.93*13/2 = x

x = 6.045 moles

Therefore 6 moles of oxygen are required to burn Butane.

To know more about Combustion Reaction

brainly.com/question/12172040

#SPJ1

6 0
2 years ago
Boron has an average atomic mass of 10.81. One isotope of boron has a mass of 10.012938 and a relative abundance of 19.80 percen
Georgia [21]
The average atomic mass is calculated by the expression:

Average atomic mass = Σzₓ(Aₓ)

where zₓ is the relative abundance of an isotope and Aₓ is the atomic mass of the isotope. 

We calculate the mass of the isotope as follows:

10.81 = .1980 (10.012938) + .8020 (x)
x = 11.00 -----------> mass of the isotope

8 0
3 years ago
Read 2 more answers
Which statements is true about electrons in their energy levels
denis-greek [22]

Answer:

Explanation:  what is the options?

3 0
4 years ago
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