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jasenka [17]
4 years ago
5

The mean cost for each item in his bag was $3.05. He bought a total of 8 items, and the prices of 7 of those items are listed be

low: $2.75,$2.89,$3.57,$2.81,$3.37,$2.70,$2.48 determine the price of the 8th item in his bag.
Mathematics
1 answer:
Anna007 [38]4 years ago
5 0

You know the mean cost is calculated from ...

... (mean cost) = (total cost)/(number of items)

You are given the mean cost and the number of items, so you can find the total cost for the 8 items as ...

... (mean cost)×(number of items) = (total cost)

... 8 × $3.05 = (total cost) = $24.40

You are given the costs of 7 of the items so ...

... (total cost) = (8th item cost) + (total cost of 7 items)

Then we can find the (8th item cost) as ...

... (8th item cost) = (total cost) - (total cost of 7 items)

Adding up the given cost of the 7 items, we get ...

... (total cost of 7 items) = $20.57

... (8th item cost) = $24.40 -20.57 = $3.83

The price of the 8th item in the bag was $3.83.

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a) P=0.8

b) P=0.67

c) P=0.05

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This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

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This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

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c. What is the probability that the household has only a cell phone and does not have high-speed Internet?

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d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?

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e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?

This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).

P(\bar C\&I)=P(I)-P(I|C)*P(C)=0.65-0.8*0.2=0.65-0.2=0.45

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