Answer:
a. 4 m/s b. 0.2 V
Explanation:
a. Find the flow rate through a 3.00-cm-diameter pipe if the Hall voltage is 60.0 mV.
The hall voltage V = vBd where v = flow-rate, B = magnetic field strength = 0.500 T and d = diameter of pipe = 3.00 cm = 0.03 m
Since V = vBd
v = V/Bd given that V = 60.0 mV = 0.060 V, substituting the values of the other variables, we have
v = 0.060 V/(0.500 T × 0.03 m)
v = 0.060 V/(0.015 Tm)
v = 4 m/s
b. What would the Hall voltage be for the same flow rate through a 10.0-cm-diameter pipe with the same field applied?
Since the hall voltage, V = vBd and v = flow-rate = 4 m/s, B = magnetic field strength = 0.500 T and d' = diameter of pipe = 10.0 cm = 0.10 m
Substituting the variables into the equation, we have
V = vBd
V = 4 m/s × 0.500 T × 0.10 m
V = 0.2 V
Answer:
Please see below as the answer is self-explanatory.
Explanation:
- In order to have a destructive interference, the path difference between the sources of the sound, must be equal to an odd multiple of the semi-wavelength, as follows:
- The minimum posible value for this distance, is when n=1, as it can be seen here:
- In any traveling wave, there exists a fixed relationship between the wave speed, the frequency and the wavelength:
- Therefore, assuming that the speed of sound keeps constant, if the frequency is increased, in order to keep the right side of the expression above balanced, λ must be decreased.
- As the smallest separation that produces destructive interference is directly proportional to the wavelength, this means that this separation will decrease if the cellists produced a note with a higher frequency.
Answer:
by doing the test over and over again until you get the right results
Explanation:
<h3><u>Answer</u> :</h3>
First of all, See the attachment for better understanding
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❂ <u>Weight of block A</u> :
➝ mg sin30° = 18
➝ W (1/2) = 18
➝ W = 18×2
➝ <u>W = 36N </u>
❂ <u>Weight of block B</u> :
➝ N sin30° = 18
➝ (Mg cos30°) sin30° = 18
➝ W' (√3/2)(1/2) = 18
➝ W' (√3/4) = 18
➝ W' = 72/√3
➝ <u>W' = 41.61N</u>
Dependent Variable=Responding Variable.